Answer:
Step-by-step explanation:
Directions
- Draw a circle
- Dear a chord with a length of 24 inside the circle. You just have to label it as 24
- Draw a radius that is perpendicular and a bisector through the chord
- Draw a radius that is from the center of the circle to one end of the chord.
- Label where the perpendicular radius to the chord intersect. Call it E.
- You should get something that looks like the diagram below. The only thing you have to do is put in the point E which is the midpoint of CB.
Givens
AC = 13 inches Given
CB = 24 inches Given
CE = 12 inches Construction and property of a midpoint.
So what we have now is a right triangle (ACE) with the right angle at E.
What we seek is AE
Formula
AC^2 = CE^2 + AE^2
13^2 = 12^2 + AE^2
169 = 144 + AE^2 Subtract 144 from both sides.
169 - 144 = 144-144 + AE^2 Combine
25 = AE^2 Take the square root of both sides
√25 = √AE^2
5 = AE
Answer
The 24 inch chord is 5 inches from the center of the circle.
Answer:
sorry the equation is confusing
Step-by-step explanation:
and pls fix it and thx.
The graph of g(x) = f(x) + 5 will have the graph of f(x) moved 5 units upward. The best choice is the last one.
_____
Adding 5 to each y-value (the output of f(x)) moves it upward by 5 units.
26+26=52 which is the side lengths.
116-52=64 which is the other side lengths together. So one side length 32. 32+32+26+26=116
The distance from Ship B to the signal fire at point C is 
Explanation:
It is given that two ships A and B are at a distance 140 ft from each other.
The angle formed by ship A is 82º and the angle formed by ship B is 78º.
To determine the distance from ship B to the signal fire at point C, we need to know the another angle.
Hence, we have,

Now, we shall solve the problem using the law of sines,

Substituting the values, we have,


Simplifying, we get,


Thus, the distance from Ship B to the signal fire at point C is 