Answer:
ok lol
Step-by-step explanation:
Answer:
They are taking 12 2 credit courses
The are taking 4 1 credit courses
Step-by-step explanation:
x = 1 credit courses
y = 2 credit courses
The number of courses is 16
x+y = 16
The number of credits is 28 so multiply the course by the number of credits
1x+2y=28
Subtract the first equation from the second equation
x+2y =28
-x-y=-16
-----------------
y = 12
They are taking 12 2 credit courses
We still need to find the 1 credit courses
x+y = 16
x+12= 16
Subtract 12 from each side
x-12-12 = 16-12
x =4
The are taking 4 1 credit courses
Answer:
24
Step-by-step explanation:
pls mark me brainless pls
We have
<span>Va(airplane)=150
East</span>
Vw(wind)=7.1
South East
<span>
</span><span>resulting vector R</span>
airplane
Vax=150 Vay=0 it only has component x
WindVwx=7.1*cos45=5.02
Vwy=7.1*sin45=-5.02
is negative because is South direction
|R|=(Rx^2+Ry^2) ^0.5
Rx=150+5.02=155.02
Ry=0-5.02=-5.02
<span>|R|=155.10
miles/hour South East</span>
Determine angle θ
Rx=R*cos(θ)
<span>Cos(θ)=Rx/R</span>
<span>Cos(θ)=155.02/155.10=0.9995</span>
θ =arc cos Rx/R
θ =1.8119 º
Rx represents the component in the East direction of the resultant force. Your contribution is given by both, the force of the plane and the wind. The contribution of the wind makes the airplane's speed greater
Ry represents the component in the South direction of the resulting force
Its contribution is exclusive of the wind since the airplane has no component
in this direction
|R| the force resulting from the combined action of the force of the plane and the force of the wind
θ represents the angle that forms the resultant force with respect to the x axis or east direction
