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denis23 [38]
3 years ago
5

Find a6 for an arithmetic sequence where a1=3x+1 and d=2x+6​

Mathematics
2 answers:
abruzzese [7]3 years ago
7 0

Answer:

a₆ = 13x + 31

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

Here a₁ = 3x + 1 and d = 2x + 6 , then

a₆ = 3x + 1 + 5(2x + 6)

    = 3x + 1 + 10x + 30

    = 13x + 31

irinina [24]3 years ago
7 0
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2(a-7)=a+4<br> 15 6<br>PLS HELPPPPPPPPPPP​
muminat

Answer:

a = 18

Step-by-step explanation:

2(a-7)=a+4

Distribute 2 into left side: 2a -14 = a + 4

subtract a from both sides  2a-a-14 = a+4-a

Simplify: a  - 14 = 4

Add 14 to both sides: a - 14 + 14 = 4 +14

Simplify:   a = 18

If wanted, plug a into original to double check work:

plug in: 2 (18-7) = 18+4

do parenthesis first: 2 (11) = 18+4

do multiplication : 22 = 18+4

additions: 22 =22

a = 18 is correct.

8 0
3 years ago
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2 years ago
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2/5 m = ____ cm<br><br><br><br> 5/6 year = _____ months <br><br><br> ONLY IN FRACTION
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Step-by-step explanation:

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Answer:

x 2 y -4

Step-by-step explanation:

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