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3 years ago

5

Find a6 for an arithmetic sequence where a1=3x+1 and d=2x+6

2 answers:

abruzzese [7]3 years ago

7 0

Answer:

a₆ = 13x + 31

Step-by-step explanation:

The nth term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

Here a₁ = 3x + 1 and d = 2x + 6 , then

a₆ = 3x + 1 + 5(2x + 6)

= 3x + 1 + 10x + 30

= 13x + 31

irinina [24]3 years ago

7 0

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