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mart [117]
3 years ago
6

USA test prep wave 1 performance task

Chemistry
1 answer:
Contact [7]3 years ago
7 0

Answer:

Performance Tasks 188; Instructional Videos 75

Explanation:

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Answer the following questions about the fermentation of glucose (C6H12O6, molar mass 180.2 g/mol)
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The amount of energy in kilocalories released from 49 g of glucose given the data is -4.4 Kcal

How to determine the mole of glucose

Mass of glucose = 49 g

Molar mass of glucose = 180.2 g/mol

Mole of glucose = ?

Mole = mass / molar mass

Mole of glucose = 49 / 180.2

Mole of glucose = 0.272 mole

How to determine the energy released

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