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musickatia [10]
3 years ago
9

A certain first-order reaction has a rate constant of 2.65×10−2s−1 at 16 ∘C. What is the value of k at 63 ∘C if Ea = 88.5 kJ/mol

?
Chemistry
1 answer:
alisha [4.7K]3 years ago
5 0

Answer:

chemistry ka mujy b krna☹️

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Why must protein digesting enzymes be stored in the inactive form
max2010maxim [7]

Answer:

To shield the organs and glands from the enzymes' digestion, protein digesting enzymes are released in an inactive state. If they are discharged in an active state, they begin digesting the glands that transport them as well as the release site.

Explanation:

8 0
2 years ago
Magnesium Oxide decomposes to produce 3.54 grams of oxygen gas. How many grams of magnesium oxide decomposed?
sukhopar [10]
<h2>Let us solve for it </h2>

Explanation:

Magnesium oxide

  • It is MgO  
  • Its molecular mass is : 24 +16=40 g
  • When MgO decomposes it forms = 3.54 g of oxygen gas  
  • when 40 g of MgO decomposes it forms = 16g of oxygen  
  • or we can say that :
  • 16g of oxygen is produced when 40 g of MgO is decomposed .
  • 1g of oxygen will be formed from =40/16g of MgO  
  • 3.54 g of oxygen will be formed = 40/16 x 3.54 =8.85g of MgO  

4 0
3 years ago
4. A 14.5-L balloon is in the air where it is 20.0 C at 0.980-atm. A wind passes over and the balloon's pressure becomes 740.0-m
jeka94

The temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.

<h3>What is Combined gas law?</h3>

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

  • Initial volume V₁ = 14.5L
  • Initial pressure P₁ = 0.980atm
  • Initial temperature T₁ = 20.0°C = 293.15K
  • Final volume V₂ = 14.3L
  • Final pressure P₂ = 740.mmHg = 0.973684atm
  • Final temperature T₂ = ?

We substitute our given values into the expression above.

P₁V₁/T₁ = P₂V₂/T₂

( 0.980atm × 14.5L )/293.15K = ( 0.973684atm × 14.3L )/T₂

14.21Latm / 293.15K = 13.92368Latm / T₂

14.21Latm × T₂ = 13.92368Latm × 293.15K

14.21Latm × T₂ = 4081.72679LatmK

T₂ = 4081.72679LatmK / 14.21Latm

T₂ = 287.24K

T₂ = 14.09°C

Therefore, the temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.

Learn more about the combined gas law here: brainly.com/question/25944795

#SPJ1

4 0
2 years ago
If 1.6 moles of an ideal gas are at a temperature of 25c and a pressure of 0.91 atm hg, what volume would the gas occupy, in lit
Fiesta28 [93]
From\ Ideal\ Gas\ Law:\\\\PV=nRT\\\\&#10;P-pressure\\V-volume\\n-number\ of\ moles\\R- universal\ gas\ constant\\T-absolute\ tmeperature\\\\&#10;R=\ 8,3145J/ mol\ K\\P=0,91atm\\&#10;n=1,6moles\\T=25c\\\\&#10;Converting\ units:\\\\&#10;1atm=101,3kPa=101,3*10^3\\&#10;0,91atm=0,91*101,3*10^3=92,183*10^3Pa\\T=25c=273+25=298K\\\\&#10;V=\frac{nRT}{P}=\frac{1,6*8,3145*298}{92183}=0,043m^3=43liters\\\\Answer\ is\ 43\ liters.
8 0
3 years ago
3. Give three examples of a pure substances
Nadya [2.5K]

Answer:

There will be weight, there will be volume, there will be height

Explanation:

5 0
3 years ago
Read 2 more answers
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