Answer:
The correct answer is 5,170 J
Explanation:
The heat absorbed by the reaction (Qr) is equal to the heat released by the calorimeter (Qcal):
Qr = - Qcal
We calculate Qcal from the mass of the calorimeter (m), the specific heat (Cp), and the change in temperature (ΔT), as follows::
Qcal = m x Cp x ΔT
We have the following data:
m = 1.400 kg x 1000 g/1 kg = 1,400 g
Cp = 3.52 J/g°C
Initial T = 28.50°C + 273 = 301.50 K
Final T = 27.45°C + 273 = 300.45 K
ΔT = Final T - Initial T = 300.45 K - 301.50 K = -1.05 K
So, we introduce the data in the mathematical expression for Qcal:
Qcal = m x Cp x ΔT = 1,400 g x 3.52 J/g°C x (-1.05 K) = -5,174.4 J ≅ -5,170 J
Therefore, the heat absorbed by the reaction is:
Qr = - Qcal = -(-5,170 J) = 5,170 J
