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3 years ago

Part A

Chemistry

1 answer:

abruzzese [7]3 years ago

6 0

117 mL of 0.210 M K₂S solution

Explanation:

The question asks about the volume of 0.210 M K₂S (potassium sulfide) solution required to completely react with 175 mL of 0.140 M Co(NO₃)₂ (cobalt(II) nitrate).

We have the chemical reaction:

K₂S + Co(NO₃)₂ → CoS + 2 KNO₃

molar concentration = number of moles / volume (L)

number of moles = molar concentration × volume

number of moles of Co(NO₃)₂ = 0.140 × 175 = 24.5 mmoles

We see from the chemical reaction that 1 mmole of Co(NO₃)₂ is reacting with 1 mmole of K₂S, so 24.5 mmoles of Co(NO₃)₂ are reacting with 24.5 mmoles of K₂S.

volume = number of moles / molar concentration

volume of K₂S solution = 24.5 / 0.210 = 117 mL

Learn more about:

molar concentration

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