1) The lengths of the other 2 sides are 51 feet.
Isosceles triangles have at least 2 equal sides. The base is 60 feet, so we can assume that the other 2 sides are equal
162 = 60 + 2x
x = the equal sides of the triangle.
162 - 60 = 102
102 = 2x
Divided by 2
51 = x
51 + 51 = 102. 102 + 60 = 162
2)
Pool 1: 311.38ft.
8*19.4 = 155.2
8 * 5.7 * 2 = 91.2
5.7 * 5.7 = 32.49/2 (because its a triangle) = 16.254*4 = 64.98
155.2 + 91.2 + 64.98 = 311.39
Pool 2: Either 863.94ft or 484 + 121πft
22 * 22 = 484
22/2 = 11, So, the radius of the half circle is 11
Circle area = (pi)r^2
11*11 = 121
pi * 121 = 121pi
Using 3.14 substitute: 3.14 * 121 = 379.94
379.94 + 484 = 863.94
Pool 3: 207ft
Rhombus area = pq/2
18 * 12 = 216
216/2 = 108
11 * 18 = 198/2 = 99
99 + 108 = 207
Using the empirical rule 68% would fall within one standard deviation of the mean.
The standard deviation is given as 2 inches and the mean is 49 inches.
Since it is only one standard deviation find the lower number by subtracting the standard deviation from the mean and find the higher number by adding the standard deviation to the mean.
49 - 2 = 47
49 + 2 = 51
68% would be between 47 inches and 51 inches tall.
Answer: =−q+48.929073 <-- coming frm a calculator lol
Step-by-step explanation:
