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Artyom0805 [142]
3 years ago
14

Help help help help help

Mathematics
1 answer:
lbvjy [14]3 years ago
6 0

Answer:

5 times the sum of a number and 7 --> 5(n+7)

5 less than the quotient of eight and a number increased by 7 --> 8/n-5+7

8 more than the product of 7 and a number decreased by 2 --> 8+7n-2

Twice the difference of 8 and a number --> 2(8-n)

Step-by-step explanation:

Hope this helps!!

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Classify the following triangle. Check all that apply.
GaryK [48]
A and E I think because isosceles is two equal and one different and Right because it has a right/90° angle
4 0
3 years ago
Arrange the pairs of points in increasing order of the slopes of the lines joining them. (15, 30) and (20, 40)
gavmur [86]

Answer: m1 = 0.5

M2= 0.375

M3 = 2.25

M4 = 3.0

M5 = 13.5

M6 = 0.285

M7 = 7.0

Step-by-step explanation:

(20,40)-(15,30)=(5,10), m1=5/10=0.5

(18,48)-(12,32)=(6,16), m2=3/8=0.375

(72,32)-(27,12)=(45,20), m3=9/4=2.25

(60,20)-(45,15)=(15,5), m4=3.0

(243,18)-(27,2)=(216,16), m5=27/2=13.5

(24,84)-(18,63)=(6,21), m6=2/7=0.285...

(84,12)-(63,9)=(21,3), m7=7.0

4 0
3 years ago
An object is 3.6 m from the pinhole. Its image is 4.2 cm from the opposite side of the pinhole. The height of the image is 0.8 c
madreJ [45]

Answer:

Height of the object is 68.6 cm.

Step-by-step explanation:

The height of the object can be determined by:

\frac{object distance from pinhole}{image distance from pinhole} = \frac{object height}{image height}

From the given question;

object distance from pinhole = 3.6 m = 360 cm

image distance from pinhole = 4.2 cm

height of image = 0.8 cm

So that;

\frac{360}{4.2} = \frac{object height}{0.8}

⇒ object height = \frac{360*0.8}{4.2}

                           = \frac{288}{4.2}

                           = 68.571

object height = 68.6 cm

Thus, the height of the object is 68.6 cm.

5 0
3 years ago
A 6-sided die is rolled.
Rufina [12.5K]

Answer:

Step-by-step explanation:

P(A∪B) = 1/6 + 1/2 = 2/3

7 0
2 years ago
Express sin A,cos A and tan A as ratios
OverLord2011 [107]

Answer:

Part A) sin(A)=\frac{2\sqrt{42}}{23}

Part B) cos(A)=\frac{19}{23}

Part C) tan(A)=\frac{2\sqrt{42}}{19}

Step-by-step explanation:

Part A) we know that

In the right triangle ABC of the figure the sine of angle A is equal to divide the opposite side angle A by the hypotenuse

so

sin(A)=\frac{BC}{AB}

substitute the values

sin(A)=\frac{2\sqrt{42}}{23}

Part B) we know that

In the right triangle ABC of the figure the cosine of angle A is equal to divide the adjacent side angle A by the hypotenuse

so

cos(A)=\frac{AC}{AB}

substitute the values

cos(A)=\frac{19}{23}

Part C) we know that

In the right triangle ABC of the figure the tangent of angle A is equal to divide the opposite side angle A by the adjacent side angle A

so

tan(A)=\frac{BC}{AC}

substitute the values

tan(A)=\frac{2\sqrt{42}}{19}

8 0
3 years ago
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