Given m||n, find the value of x.<br><br> (7%-10)<br> (6X-5)

A recent physical inventory at a department store reports a merchandise value of $875,435. The merchandise book value was $907,3

Vlad [161]

Answer:

The shrinkage as a percentage of sales is 1.6%.

Step-by-step explanation:

In order to find the percentage of the sales that can be contributed to shrinkage, we first need to find the amount of shrinkage between the book value ($907,340) and the physical inventory ($875,435). The difference between these two values is $31,905. With this value of shrinkage, I then divide by the total amount in sales, which is $1,988,345. This would give me an overall percentage of 1.6%, which represents the shrinkage as a percentage of sales.

5 0

3 years ago

Increase- From 20 miles to 11 miles

xenn [34]

HshahahahauAiajwhwbahah

7 0

2 years ago

HURRY AND ANSWER

Dennis_Churaev [7]

24+28.5−8=44.5 ft^2

The total area is 44.5 ft^2.

4 0

2 years ago

Read 2 more answers

The percent frequency distributions of job satisfaction scores for a sample of information systems (IS) senior executives and mi

tiny-mole [99]

Corrected Question

a. Develop a probability distribution for the job satisfaction score of a senior executive.

b. Develop a probability distribution for the job satisfaction score of a middle manager.

c. What is the probability a senior executive will report a job satisfaction score of 4 or 5?

d. What is the probability a middle manager is very satisfied?

Answer:

(c)0.83

(d)0.28

Step-by-step explanation:

The percent frequency distributions of job satisfaction scores os give below:

$\left|\begin{array}{c|c|c}$Job Satisfaction Score&$IS Senior Executives(\%)&$IS Middle Managers(\%)\\1&5&4\\2&9&10\\3&3&12\\4&42&46\\5&41&28\end{array}\right|$

(a)Probability distribution for the job satisfaction score of a senior executive.

$\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_1(x))\\------&------\\1&0.05\\2&0.09\\3&0.03\\4&0.42\\5&0.41\end{array}\right|$