Step-by-step explanation:
again, 2 unknowns.
x = number of 2- points baskets
y = number of 3- points baskets
we know they hit the basket 37 times in a so far unknown mixture of 2-point and 3- point throws.
x + y = 37
which gives us e.g.
x = 37 - y
and we know that with this unknown mixture they scored 80 points.
so,
2x + 3y = 80
as every successful 2-points throw scores 2 points, and every successful 3-points throw scores 3 points.
so, again our 2 equations :
x = 37 - y
2x + 3y = 80
remember, we prepared the first equation so that it gives us already an identity expressing one variable by the other. and that we use in the second equation :
2×(37 - y) + 3y = 80
74 - 2y + 3y = 80
74 + y = 80
y = 6
and from
x = 37 - y
we get
x = 37 - 6 = 31
so, they had 31 2-points throws and 6 3-points throws.
For line A,
if we increase x by 1 unit then y increases by 4 units i.e. (1,3) and similarly another point becomes
(2,7).
For line B,
if we increase x by 1 uni then y also increases by 1 unit i.e ( 1,1) and similarly another points becomes (2,2),(3,3),(4,4), etc.
For line C,
if we increase x by 3 units then y increases by 1 units i.e.(3,1) and similarly another points becomes
(7,2) and so on.
In above lines, the value of x is exactly equal to that of y in line B.
therefore, line B has constant proportionality between x and y.
Answer:
The GCF for 15az and 25az is marked below.
15az = 3*5*a*z
25ab - 5*5*a*b
GCF = 5a
Step-by-step explanation:
Answers above! Hoped this helped :)
The first term of this series (a+1) is 1 and the common ratio (r) is -3.
Thus, the explicit formula is a_n = 1*(-3)^(n-1).
Must check this! suppose we try to calculate the 3rd term. Then n = 3.
a_3 = 1*(-3)^(3-1) = (-3)^2 = 9. This is correct.
