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umka2103 [35]
3 years ago
12

Ax + By > C In Which Form is this linear inequality?

Mathematics
1 answer:
liq [111]3 years ago
4 0

Answer: A

Step-by-step explanation:

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Im not positive but im pretty sure it's 27
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Is 2.315 more than 2.3
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Yes, 2.315 is greater than 2.3. Please mark me brainiest! :)
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5-4(n+2)=18 what is n
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5-4(n+2)=18 


-4(n+2)=18-5
 

  Subtract \ 5 \ from  \ both \ sides
 

-4(n+2)=13

 

n+2= \dfrac{13}{-4}    Divide \ both \ sides \ by \ -4

<span>n+2= -\dfrac{13}{4}  
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<span>n+2= -\dfrac{13}{4}-2    </span>Subtract \ 2 \ from \ both \ sides&#10;<span>
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n=- \dfrac{21}{4}

Decimal \ Form: -5.25
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????????????????????????
choli [55]

Answer: 12

Step-by-step explanation:

\frac{6}{18}=\frac{4}{c}

Solve for c

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3 0
3 years ago
A consumer advocacy group wants to determine whether there is a difference between the proportions of the two leading automobile
podryga [215]

Answer:

The answer is "0.3206".

Step-by-step explanation:

H_0: p_1 = p_2\\\\H_a: p_1 \neq  p_2\\\\\hat{p_1} = \frac{X_1}{N_1} = \frac{53}{400} = 0.1325\\\\\hat{p_1}= \frac{X_2}{N_2} = \frac{78}{500}= 0.156\\\\\hat{p} = \frac{(X_1 + X_2)}{(N_1 + N_2)} = \frac{(53+78)}{(400+500)} = 0.1456

Testing statistic:

z = \frac{(\hat{p_1}- \hat{p_2})}{\sqrt{(\hat{p} \times (1-\hat{p}) \times (\frac{1}{N_1} + \frac{1}{N_2}))}}

=\frac{(0.1325-0.156)}{\sqrt{(0.1456\times (1-0.1456)\times (\frac{1}{400} + \frac{1}{500}))}}\\\\ = -0.99

Calculating the P-value Approach

\text{P-value}= 0.3206

7 0
3 years ago
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