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Darya [45]
3 years ago
6

The triangle is 30° -60° -90° triangle. A landscaper plans to build a bridge across the pond from point R to point T. Which meas

ureis closest to the length of RT?
A) 20.0 ft. B) 34.6 ft.
C) 40.0 ft. D) 69.2 ft.
Mathematics
2 answers:
liubo4ka [24]3 years ago
7 0
The Correct Answer Is D
vivado [14]3 years ago
4 0
Wait we should have one of the sides
 also which side is RT?
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The difference of two numbers is 16 and the sum of their squares is 130. What are the numbers.
Korvikt [17]
x - y = 16
x^2 + x^2 = 130

----------------
x^2 - y^2 = 256
+(x^2 + y^2 = 130)
2x^2 = 386
x^2 = 193
x = <span>13.892 (3DP)
----
</span>x - y = 16
13.892 - y = 16
-y = 2.108
y = -2.108
The numbers are: 13.892 and -2.108
4 0
3 years ago
Find the volume of the solid under the plane 5x + 9y − z = 0 and above the region bounded by y = x and y = x4.
svp [43]
<span>For the plane, we have z = 5x + 9y

For the region, we first find its boundary curves' points of intersection.
x = x^4 ==> x = 0, 1.

Since x > x^4 for y in [0, 1],

The volume of the solid equals

\int\limits^1_0 { \int\limits_{x^4}^x {(5x+9y)} \, dy } \, dx = \int\limits^1_0 {\left[5xy+ \frac{9}{2} y^2\right]_{x^4}^{x}} \, dx  \\  \\ =\int\limits^1_0 {\left[\left(5x(x)+ \frac{9}{2} (x)^2\right)-\left(5x(x^4)+ \frac{9}{2} (x^4)^2\right)\right]} \, dx  \\  \\ =\int\limits^1_0 {\left(5x^2+ \frac{9}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx =\int\limits^1_0 {\left( \frac{19}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx \\  \\ =\left[ \frac{19}{6} x^3- \frac{5}{6} x^6- \frac{1}{2} x^9\right]^1_0

=\frac{19}{6} - \frac{5}{6} - \frac{1}{2} =\bold{ \frac{11}{6} \ cubic \ units}</span>
8 0
3 years ago
-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
3 years ago
John is going on a trip and the country he is traveling to uses the Celsius scale. He is curious about converting Celsius temper
Setler79 [48]

Answer:

f(x)=\dfrac{9}{5}x+32 converts Celsius to Fahrenheit.

g(x)=\dfrac{5(x-32)}{9} converts Fahrenheit to Celsius.

Step-by-step explanation:

Write given data in the table

\begin{array}{cc}x&f(x)\\^{\circ}\text{C}&^{\circ}\text{F}\\20&68\\30&86\end{array}

Let the expression for the function be

f(x)=ax+b

Note, that this equation is linear equation and it is well-known fact that the Celsius to Fahrenheit dependence is linear.

Substitute corresponding values into this expression:

68=20a+b\\ \\86=30a+b

Subtract these two equations:

86-68=30a-20a\\ \\10a=18\\ \\a=\dfrac{9}{5}

Substitute it into the first equation:

68=20\cdot \dfrac{9}{5}+b\Rightarrow b=68-36=32

So,

f(x)=\dfrac{9}{5}x+32

This is the function which converts Celsius to Fahrenheit.

And function

g(x)=\dfrac{5(x-32)}{9} converts Fahrenheit to Celsius.

4 0
3 years ago
Read 2 more answers
A number b increased by 3 is greater than or equal to -26
photoshop1234 [79]

A number b increased by 3 is greater than or equal to -26:

b+3\geq-26\qquad\text{subtract 3 from both sides}\\\\\boxed{b\geq-29}

5 0
3 years ago
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