Name three decimals between 16.4 and 16.5. Draw a number line estimating the placement off all five decimals.

1 answer:

7 0

16.42 and 16.43 and 16.44 It ranges from any numbers between 16.40-16.50

Remember that there is an imaginary 0 next to the tenths place.

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Simplify -8y + 4(11y - 3)

erica [24]

-8y + 4(11y - 3) =
-8y + 44y - 12 =
36y - 12 <==

4 0

4 years ago

2/6, 2/4, 2/10 please help with my with this like hurry when you see this pleaseeeee

Vikentia [17]

Answer:

Step-by-step explanation:

I’m not sure if u mean dividing but this is dividing..2/6=3 2/4=2 2/10=5

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4 years ago

Which images shows a reflection

leonid [27]

I'll Give You Some Hints:

Let's Look at C.

In C, the triangle is translated 2 units to the right. Which means that it cannot be a reflection.

Let's Look at B.

In B there is a sideways triangle. That means it's a Rotation. Which means it's not Reflected.

Lastly, Let's Look at A.

To get from the original triangle to the triangle in A, you have to reflect twice. Once along a vertical line, and then along a horizontal line.

This Information Should Help You

7 0

3 years ago

Triangle ABC has vertices at A(1,2) B(4,6) and C(4,6) in the coordinate plane. The triangle will be reflected over the x-axis an

k0ka [10]

You should know that you can predict changes in coordinates after translations without a graph or anything like that.

(x, y) reflected over the x axis = (x, -y)
(x, y) reflected over the y axis = (-x, y)
(x, y) rotated 90 degrees around the origin = (y, -x)
(x, y) rotated 180 degrees around the origin = (-x, -y)
(x, y) rotated 270 degrees around the origin - (-x, y)

So here's our set of points.
A(1, 2), B(4, 6), C(4, 6)

Here's those points reflected over the x axis.
A'(1, -2), B'(4, -6), C'(4, -6)

And here's <em>those</em> points rotated 180° around the origin.
A''(2, -1), B''(6, -4), C''(6, -4)

I think you made a mistake writing down the question, though, because B and C are the same yet you say ABC forms a triangle. You should be able to go through this process with whatever the coordinate was supposed to be.

4 0

3 years ago

Derivative of y= 2^(sin pi x)

laila [671]

Take log of both sides
$\ln y = \ln(2^{\sin \pi x})$
Use log property to get "x" out of the exponent
$\ln y = (\ln 2) (\sin \pi x)$
Differentiate
$\frac{dy}{y} = (\pi \ln 2)(cos \pi x) dx$
Move y to Right side (Note y = original expression)
$\frac{dy}{dx} = (\pi \ln 2) (\cos \pi x) 2^{\sin \pi x}$

In general, whenever you have a function in the form
$y = a^{f(x)}$
The derivative will be
$\frac{dy}{dx} = (\ln a) (f'(x))a^{f(x)}$

3 0

3 years ago