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goldfiish [28.3K]
3 years ago
13

-3x + 6 - (-5) + 7x Simplify it

Mathematics
2 answers:
Vadim26 [7]3 years ago
7 0

3x+6-[-5]+7x

=3x+6+5+7x

= 3x+7x=6+5

=10x=11

=x=11/10

SO,

x=11/10

Anna11 [10]3 years ago
5 0

Answer:

4x+11

Step-by-step explanation:

-3x+7x +6+5

4x+11

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What is 3x + 10(1-7X)
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-67x + 10

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3 years ago
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Write an equation of the line that passes through the point (–1, 4) with slope 2. A. y+1=−2(x−4) B. y+1=2(x−4) C. y−4=2(x+1) D.
In-s [12.5K]

Answer:

y-4=2\,(x+1)

which agrees with answer C in your list of possible answers.

Step-by-step explanation:

We can use the general point-slope form of a line of slope m and going through the point (x_0, y_0):

y-y_0=m(x-x_0)

which in our case, given the info on the slope (2) and the point (-1, 4) becomes:

y-y_0=m\,(x-x_0)\\y-4=2\,(x-(-1))\\y-4=2\,(x+1)

6 0
3 years ago
PLSSSSSSSS HELLPPPPPP.......Which triangle’s unknown side length measures StartRoot 53 EndRoot units?
Orlov [11]

The right answer is Option 2: A right triangle with side length of √47 and hypotenuse of 10.

Step-by-step explanation:

We know that;

a^2 + b^2 = c^2

We will put the unknown length as √53 to check the solution.

Option 1: a = 6 , b = √53 , c = √91

(6)^2+(\sqrt{53})^2=(\sqrt{91})^2\\36+53=91\\89\neq 91

Option 2: a=√47, b = √53, c = 10

(\sqrt{47})^2+(\sqrt{53})^2=(10)^2\\47+53=100\\100=100

Option 3: a = √19, b=√53, c= √34

(\sqrt{19})^2+(\sqrt{53})^2=(\sqrt{34})^2\\19+53=34\\72\neq 34

Option 4: a=√73, b=√53, c=20

(\sqrt{73})^2+(\sqrt{53})^2=(20)^2\\73+53=400\\126\neq 400

Option 2 satisfies pythagoras theorem.

Therefore;

The right answer is Option 2: A right triangle with side length of √47 and hypotenuse of 10.

Keywords: pythagoras theorem, square root

Learn more about pythagoras theorem at:

  • brainly.com/question/11203617
  • brainly.com/question/11253316

#LearnwithBrainly

3 0
4 years ago
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