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goldfiish [28.3K]
2 years ago
13

-3x + 6 - (-5) + 7x Simplify it

Mathematics
2 answers:
Vadim26 [7]2 years ago
7 0

3x+6-[-5]+7x

=3x+6+5+7x

= 3x+7x=6+5

=10x=11

=x=11/10

SO,

x=11/10

Anna11 [10]2 years ago
5 0

Answer:

4x+11

Step-by-step explanation:

-3x+7x +6+5

4x+11

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Find the measures of the numbered angles in each isosceles trapezoid.
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4 0
3 years ago
#14 write the given sentence as an equation. Tim'S age in 7 years will be three times what it was 19 years ago
kobusy [5.1K]
The first thing we must do for this case is to define variables.
 We have then:
 x = Tim's age
 Now we write the equation:
 x + 7 = 3 (x-19)
 Answer:
 
Tim's age in 7 years will be three times what it was 19 years ago:
 
x + 7 = 3 (x-19)
3 0
3 years ago
Manny can assemble a computer by himself in 50 minutes. Lucy does the same job in 45 minutes. How long will it take to assemble
jonny [76]
Manny can assemble a computer in 50 minutes. That means, in a minute Manny does \frac{1}{50} job.

Lucy can assemble a computer in 45 minutes. That means, in a minute Lucy does \frac{1}{45} job.

If they are working together, in a minute they will do:
\dfrac{1}{50} + \dfrac{1}{45}
= \dfrac{9}{450} + \dfrac{10}{450} \text{(equalize the denominator)}
=\dfrac{19}{450}
In a minute they will do \frac{19}{450} job

To finish the job they will do it in \frac{450}{19} minutes or about 24 minutes.
5 0
3 years ago
For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
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