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omeli [17]
3 years ago
6

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Mathematics
1 answer:
-Dominant- [34]3 years ago
8 0
The 2nd and 3rd options
You might be interested in
ABCD is a rectangle and AC and BD are its diagonals. If AC = 10 cm, then BD is?
kiruha [24]

Answer:

A. 10 cm

Step-by-step explanation:

In a right angled triangle, a² + b² = c² where c is the diagonal or hypotenuse. If you split a rectangle diagonally into two right angle triangles, the a and b of both triangles would be the same length. Therefore, the c or diagonals would also be the same length - 10 cm.

Hope this helps!

5 0
3 years ago
Read 2 more answers
Parabola Equations - Algebra
mash [69]

Answer:

h=-\frac{1}{6}x^2+2x

Step-by-step explanation:

The height of the tunnel is modeled by:

h=rx^2+tx

Where r and t are constants.

We know that the maximum height of the tunnel h is 6 meters.

And at ground level, the width is 12 meters.

And we want to determine the equation of the parabola.

First, since this is a quadratic, our maximum height h will occur at the vertex of our equation.

The vertex is given by:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

In our case, we have the function:

h=(r)x^2+(t)x

Hence, a=r; b=t; and c=0.

Therefore, our vertex is:

\Rightarrow -\frac{t}{2r}

Thus, if we substitute this back into our equation, we should get 6 since 6 is the maximum height which is determine by the vertex. In other words:

(6)=r(-\frac{t}{2r})^2+t(-\frac{t}{2r})

Simplify:

6=r(\frac{t^2}{4r^2})-\frac{t^2}{2r}

Simplify:

6=\frac{t^2}{4r}-\frac{t^2}{2r}

Combine fractions:

6=\frac{t^2}{4r}-\frac{2t^2}{4r}=\frac{-t^2}{4r}

Multiply both sides by the denominator:

24r=-t^2

Let's solve for the constant r. Divide both sides by 24. Hence:

r=-\frac{t^2}{24}

Now, we can use our knowledge of the width.

We know that the width is 12 meters at ground level.

Hence, when h=0, the <em>difference of our roots</em> is 12.

So:

0=rx^2+tx

We can factor:

0=x(rx+t)

By the Zero Product Property:

x=0\text{ or } rx+t=0

So, the first zero is 0.

Therefore, the second zero <em>must be 12</em> to ensure that our width is 12.

Let's isolate the second zero. Subtract t from both sides:

rx=-t

Divide both sides by r:

x=-\frac{t}{r}

We know that this zero must be 12. Thus:

12=-\frac{t}{r}

We have previously solved for r. Substitute:

12=-\frac{t}{\frac{-t^2}{24}}

Simplify:

12=\frac{24}{t}

Take the reciprocal of both sides:

\frac{t}{24}=\frac{1}{12}

Multiply both sides by 24. Hence, the value of t is:

t=2

Now, we can find r. r is given by:

r=-\frac{t^2}{24}

By substituting 2 for t, then, we acquire that:

r=-\frac{(2)^2}{24}=-\frac{4}{24}=-\frac{1}{6}

Therefore, for:

h=rx^2+tx

Our equation is:

h=-\frac{1}{6}x^2+2x

7 0
3 years ago
A screening of 1,250 teenage boys shows 15 have high blood pressure. What is the probability a teenage boy will have high blood
Lyrx [107]
To find this just divide 15 by 1250 and get <span>0.012
to find the percent just multiply </span><span>0.012 by 100 : 1.2%
the answer is 1.2%</span>
4 0
3 years ago
The first three terms in a geometric progression are 144,x and 64 and x is positive find the value of Xander the sum to infinity
Scilla [17]
The answer is 9,216 Hope this helps
3 0
3 years ago
Evaluate each expression. Enter the correct answers in the boxes. (60−6)×(13)3+27÷3= ( 60 − 6 ) × ( 1 3 ) 3 + 27 ÷ 3 = 82÷4×(2+3
11Alexandr11 [23.1K]

Answer:

2115

Explanation:

To evaluate the expression (60−6)×(13)3+27÷3 we use BODMAS

BODMAS is an acronym/rule in mathematics that dictates the order we should solve mathematical operations such as the above.

BODMAS stands for bracket first, order or of, division, multiplication, addition and then lastly subtraction

To solve the expression using BODMAS, we solve the brackets first

(60−6)×(13)3+27÷3 =54×39+27/3

Then division

=54×39+9

=2106+9

Then addition

=2106+9=2115

Answer=2115

4 0
3 years ago
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