<em>My goodness, this is rather confusing in the way it is worded. Nevertheless, I will attempt to do what I can. Just please keep in mind that this is my own interpretation of the problem, and therefore could be... incorrect.</em>
<em>I think, to start out, we could set up the problem like so</em>
<em>15 + t ≥ 26</em>
<em>because t is not a set number. </em>
<em>Then all that is needed is to subtract 15 from both sides, and the equation becomes</em>
<em>t ≥ 11</em>
<em>So the resulting answer is t ≥ 11.</em>
<em />
<em>I hope that my interpretation helps.</em>
<em>-Toremi</em>
<em />
Answer:
no diagram
Step-by-step explanation:
Answers:
Q: What is the most they could weigh together?
A: 0.74 kg
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Q: What is the least they could weigh together?
A: 0.62 kg
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Work Shown:
x = weight of first ball
y = weight of second ball
each ball has a weight range of 0.31 kg to 0.37 kg, so,
add straight down to get
which simplifies to
the two soccer balls have a weight range of 0.62 to 0.74, inclusive of both endpoints.
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Without using algebra, you basically just add the smallest the two weights could be (0.31) to itself to get 0.31+0.31 = 0.62 which represents the smallest the two weights combined can be. The same happens with the largest weight of 0.37 to get 0.37+0.37 = 0.74 as the max weight of both objects together.
Answer:
6
Step-by-step explanation:
1+3=4
8÷4=2
Kindergarten = 2×1 =2
Other class = 2×3=6
Ratio of kindergarten classes to other classes is 2:6
Answer:
3
Step-by-step explanation:
Here, by reading the histogram, we will provide answer for the question asked.
We want to know how many more festivals had 18 to 23 countries represented than 0 to 5 countries.
Checking the histogram, we can see the 0-5 countries having a value of 1, while the 18-23 has a value of 4.
So, the number of more countries will be simply 4-1 = 3
