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topjm [15]
3 years ago
7

Someone help please i’ll give brainliest

Mathematics
1 answer:
iVinArrow [24]3 years ago
4 0

Answer:

shouldn't it be 11 ft ???

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The group has a 6 foot long table and a plastic tablecloth for the sale. The tablecloths package states that the tablecloth is 1
Alexxandr [17]
Yes because There are 182.2 cm in 6 feet

6 0
3 years ago
3(2−4)=−30 step by step
Margarita [4]
3•2-3•4
6-12=-30
-6=-30
false
6 0
3 years ago
The table of values represents a quadratic function. What is the average rate of change for f(x) from x = 0 to x = 10 ? Enter yo
Elena-2011 [213]
By definition we have that the average rate of change is given by:
 AVR = (f (x2) - f (x1)) / (x2 - x1)
 Substituting the values we have:
 AVR = (204 - (-6)) / (10 - 0)
 Rewriting we have:
 AVR = (204 + 6) / (10 - 0)
 AVR = 210/10
 AVR = 21
 Answer:
 
the average rate of change for f (x) from x = 0 to x = 10 is:
 
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8 0
3 years ago
If f(x) = -x2 + 6x, what is f(-3)?
Sever21 [200]

Answer:

-12

Step-by-step explanation:

f(-3)= -(-3)2 + 6(-3)

= -(-6) -18

= 6 - 18

= - 12

8 0
3 years ago
Twelve percent of U.S. residents are in their forties. Consider a group of nine U.S. residents selected at random. Find the prob
miskamm [114]

Answer:

The probability is 28 % ( approx )

Step-by-step explanation:

Since, there are only two possible outcomes in every trails ( residents are in their forties or not ),

So, this is a binomial distribution,

Binomial distribution formula,

Probability of success in x trials,

P(x)=^nC_x p^x q^{n-x}

Where, ^nC_x=\frac{n!}{x!(n-x)!}

p and q are probability of success and failure respectively and n is the total number of trials.

Let X be the event of resident who are in his or her forties.

Here, p = 12% = 0.12,

⇒ q = 1 - p = 1 - 0.12 = 0.88,

n = 9,

Hence, the probability that two or three of the people in the group are in their forties = P(X=2) + P(X=3)

^9C_2 (0.12)^2 (0.88)^{9-2}+^9C_3 (0.12)^3 (0.88)^{9-3}

=36(0.12)^2 (0.88)^7+84(0.12)^3 (0.88)^6

=0.279266611163

\approx 0.28

=28\%

7 0
3 years ago
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