<em> </em><em>Base=9cm</em>
<em>height=3</em><em> </em><em>cm</em>
<em>Area</em><em> </em><em>of</em><em> </em><em>parallelogram=b*h</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>9</em><em>*</em><em>3</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>2</em><em>7</em><em>c</em><em>m</em><em>^</em><em>2</em><em>.</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>
In order to solve this problem, we must solve an equation.
First, we need to define our unknown.
Let's call our number "n".
So, the sum of the number and 6 is the same as saying n+6
Then we need to multiply it by 2 (since it's twice the sum)
2(n+6)
This whole thing is equal to three times of the difference of the number and 8
n-8 is equal to the difference between the number and 8, then we need to multiply it by three.
3(n-8)
now, we set both sides equal and solve

The number is 36
Answer:
the answer would be the last one : g(x) = 2(x-2)² - 5
Step-by-step explanation:
I I highly recommend photomath for problems like these because you can easily type in this problem, get the answer, and it gives you a step-by-step process of how it got the answer, and it's free!
Answer:

Step-by-step explanation:
Given
Geometry Progression


Required
Calculate the second term
First, we need to write out the formula to calculate the nth term of a GP

For first term: Tn = 500 and n = 1




For fought term: Tn = 32 and n = 4


Substitute 500 for a

Make r^3 the subject


Take cube roots
![\sqrt[3]{r^3} = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Br%5E3%7D%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)
![r = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=r%20%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)

Using: 
and 




<em>Hence, the second term is 200</em>
In the formula, P is the initial amount, i is the rate, and t is the time that has passed. Simply plug in the values you know:

Rounded to the nearest cent, Maria had $2492.36 in her account after 5 years (D).