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Sauron [17]
3 years ago
14

Will mark as brainiest if it is correct!

Chemistry
1 answer:
Katen [24]3 years ago
6 0

Answer:

i am very sorry i have no answer but if i get one i can tell u the answer

Explanation:

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A flexible container at an initial volume of 6.13 L contains 6.51 mol of gas. More gas is then added to the container until it r
aivan3 [116]

Answer:

the final mole of the flexible container = 12.92 moles

Explanation:

Given that :

initial volume of a flexible container = 6.13 L

initial mole of a flexible container = 6.51 mol

final volume of a flexible container = 18.3 L

final mole of a flexible container = ???

Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Therefore,

n= \dfrac{V_2*n_1}{V_1}

n= \dfrac{18.3*6.51}{6.13}

n = 19.43

n=n_1+n_2

19.43 = 6.51 + n₂

n₂ = 19.43 - 6.51

n₂ = 12.92 moles

Thus; the final mole of the flexible container = 12.92 moles

6 0
4 years ago
What is the length of a one-dimensional box for an electron (9.109 x 10-31 kg) with an n=1 energy of 479 kJ/mol? Give the answer
OverLord2011 [107]

Answer : The length of a one-dimensional box for an electron is 2.819\times 10^{31}\AA

Explanation :

The energy level of quantum particle in a one-dimensional box is given as:

E_n=\frac{n^2h^2}{8mL^2}

where,

E_n = 479 kJ/mol = 479000 J/mol

n = energy level = 1

h = Planck's constant = 6.626\times 10^{-34}Js

m = mass of electron = 9.109\times 10^{-31}kg

L = length of a one-dimensional box = ?

Now put all the given values in the above formula, we get:

479000J/mol=\frac{(1)^2\times (6.626\times 10^{-34}Js)^2}{8\times (9.109\times 10^{-31}kg)\times L^2}

L=2.819\times 10^{21}m

conversion used : 1m=10^{10}\AA

L=2.819\times 10^{31}\AA

Therefore, the length of a one-dimensional box for an electron is 2.819\times 10^{31}\AA

3 0
3 years ago
Who made the first periodic table
ale4655 [162]
The other dude is rude wrong

The correct answer is Dmitri Mendeleev
8 0
3 years ago
Determine the rate of a reaction that follows the rate law: rate = k[A]^m[B]^n, where k = 1.5
White raven [17]
Really I appreciate you letting you guys sleep you good though I love it all I gotta see you soon buddy I’m
3 0
2 years ago
I know the answer to 13 is B and 14 is D. I just need to know why the correct answers are correct
solmaris [256]

In question 13 answer B is the correct one since a catalyst is a chemical that can be added to a reaction to increase the reaction rate without being consumed in the process. In this way, a catalyst accelerates a reaction by decreasing the energy barrier necessary for the reaction to occur or by changing the reaction mechanism. The most common types of catalysts are enzymes, acid base catalysts and heterogeneous catalysts, mostly composed of solids in which the reactants adhere.

In the reaction you have in the question, they use an acid catalyst, H3O+. This catalyst changes the reaction mechanism of 2-butene in 1-butene without being consumed, since it appears at the beginning and at the end of the transformation of 2 butene into 1-butene. The reaction mechanism would be the following

In question 14 the correct answer is option B since the law of velocity of a reaction will be governed by the slow step of the mechanism through which it occurs. In the slow step the chemical species have a harder time transforming because they need more energy to do it, then they will do it in a slower way and the reaction will take longer to occur. Therefore, the slow step is the one that will determine the total speed of the reaction and the speed law must be in terms of that process. The speed of the other two steps is so fast that it is negligible.

5 0
3 years ago
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