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belka [17]
3 years ago
12

Consider a buffer solution that is 0.50 M in NH3 and 0.20 M in NH4Cl. For ammonia, pKb=4.75. Calculate the pH of 1.0 L of the so

lution upon addition of 30.0 mL of 1.0 M HCl to the original buffer solution.
Express your answer to two decimal places.
***will mark Brainliest for right answer ***
Chemistry
1 answer:
vladimir2022 [97]3 years ago
5 0
You have 0.50 mol of NH3 and 0.20 mol of NH4+ to start (NH4Cl dissolves completely), given the molarity and 1.0 L solution.

30.0 mL of 1.0 M HCl is 0.0300 mol of HCl. This will react with the NH3 to produced 0.030 mol of NH4+.

You now have 0.47 mol NH3 and 0.23 mol NH4+. Now use the Henderson-Hasselbach equation to calculate your pH. The equation says to use concentration of acid and base, but you can just use the moles of them because it doesn’t make a difference.

pH = pKa + log(base/acid)

pKa = 14 - pKb = 14 - 4.75 = 9.25

pH = 9.25 + log(0.47/0.23) = 9.56
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What elements can on with other elements to form covalent bonds
Alenkinab [10]

Answer:

Non metals join to form covalent bond.

Explanation:

Covalent bond:

It is formed by the sharing of electron pair between bonded atoms.  

The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.

For example:

In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.

Both atoms bonded through covalent bond.

In Cl₂ both chlorine atoms are bonded through the covalent bond.

7 0
3 years ago
Determine whether each statement describes an electromagnetic wave, a mechanical wave, or both types of wave.
KiRa [710]

The question is incomplete, the complete question is;

Which statement describes a difference between electromagnetic and mechanical waves?

A. Mechanical waves cannot be longitudinal, but electromagnetic waves can.

B. Electromagnetic waves cannot move particles, but mechanical waves can.

C. Electromagnetic waves do not require a medium, but mechanical waves do.

D. Mechanical waves do not transfer energy, but electromagnetic waves do.

Answer:

Electromagnetic waves do not require a medium, but mechanical waves do.

Explanation:

A wave is defined as a disturbance along a medium which transfers energy. Waves may be classified as mechanical waves or electromagnetic waves based on their medium of propagation.

A mechanical wave requires a material medium for propagation. An example of a mechanical wave is sound waves. Sound waves are propagated in air.

Electromagnetic waves do not require a material medium for propagation. They can travel through space. An example of electromagnetic waves is light waves.

8 0
3 years ago
What is the molarity of a solution that contains 9.63 grams of hcl in 1.5 liters of solution
Aleonysh [2.5K]
Molar mass HCl = 36.5 g/mol

number of moles:

mass of solute / molar mass:

9.63 / 36.5 => 0.263 moles

Volume = 1.5 L

M = n / V

M = 0.263 / 1.5

M = 0.1753 mol/L

espero ter ajudado!
8 0
3 years ago
Read 2 more answers
Given the standard enthalpies of formation for the following substances, determine
Novosadov [1.4K]

Answer:

C

Explanation:

5 0
3 years ago
What is the solubility of ethylene (in units of grams per liter) in water at 25 °C, when the C2H4 gas over the solution has a pa
vredina [299]

<u>Answer:</u> The solubility of ethylene gas in water is 9.16\times 10^{-2}g/L

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{C_2H_4}=K_H\times p_{C_2H_4}

where,

K_H = Henry's constant = 4.78\times 10^{-3}mol/L.atm

C_{C_2H_4} = molar solubility of ethylene gas = ?

p_{C_2H_4} = partial pressure of ethylene gas = 0.684 atm

Putting values in above equation, we get:

C_{C_2H_4}=4.78\times 10^{-3}mol/L.atm\times 0.684atm\\\\C_{C_2H_4}=3.27\times 10^{-3}mol/L

Converting this into grams per liter, by multiplying with the molar mass of ethylene:

Molar mass of ethylene gas = 28 g/mol

So, C_{C_2H_6}=3.27\times 10^{-3}mol/L\times 28g/mol=9.16\times 10^{-2}g/L

Hence, the solubility of ethylene gas in water is 9.16\times 10^{-2}g/L

6 0
4 years ago
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