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belka [17]
3 years ago
12

Consider a buffer solution that is 0.50 M in NH3 and 0.20 M in NH4Cl. For ammonia, pKb=4.75. Calculate the pH of 1.0 L of the so

lution upon addition of 30.0 mL of 1.0 M HCl to the original buffer solution.
Express your answer to two decimal places.
***will mark Brainliest for right answer ***
Chemistry
1 answer:
vladimir2022 [97]3 years ago
5 0
You have 0.50 mol of NH3 and 0.20 mol of NH4+ to start (NH4Cl dissolves completely), given the molarity and 1.0 L solution.

30.0 mL of 1.0 M HCl is 0.0300 mol of HCl. This will react with the NH3 to produced 0.030 mol of NH4+.

You now have 0.47 mol NH3 and 0.23 mol NH4+. Now use the Henderson-Hasselbach equation to calculate your pH. The equation says to use concentration of acid and base, but you can just use the moles of them because it doesn’t make a difference.

pH = pKa + log(base/acid)

pKa = 14 - pKb = 14 - 4.75 = 9.25

pH = 9.25 + log(0.47/0.23) = 9.56
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6.285×10^3 mg = _____? _____ kg
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The standard enthalpy of formation (ΔH_f) is a measure of the energy released or consumed when one mole of a substance is created under standard conditions from its pure elements.

Standard enthalpies (ΔH_f) of formation for given reaction is 978.3 kJ

<h3>What is Standard enthalpies of formation?</h3>

The standard enthalpy of formation is defined as the enthalpy change when one mole of a substance in the standard state (1 atm of pressure and 298.15 K) is formed from its pure elements under the same conditions.

Given reaction ;

N_2O_4(g) + 4H_2 (g) - > N_2(g) + 4H_2O(g)

To Find : ΔH_f

ΔH_f = ∑np ΔH_f (products) – ∑np ΔH_f (reactants)

ΔH_f = [1(ΔH_f N_2) + 4(ΔH_f H_2O)] – [1(ΔH_f N_2O_4) + 4(ΔH_f H_2)]

ΔH_f = [1(0) + 4(-241.8)] – [1(+9.16) + 4(0)]

ΔH_f  = [4(-241.8)] – [1(+9.16)] = 978.3 kJ

Learn more about Enthalpy here ;
brainly.com/question/16720480

#SJF1

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