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2 years ago

What is the solution and solvent in Kool-Aid?

2 answers:

5 0

In this solution the solvent is water and the solutes are sugar, artificial flavor and artificial color. Another interesting property of solutions is that different concentrations of solute can be made. As all of you are aware, you can make very sweet Kool Aid and less sweet Kool Aid.

Andrej [43]2 years ago

4 0

Answer:

In this solution the solvent is water and the solutes are sugar, artificial flavor and artificial color. Another interesting property of solutions is that different concentrations of solute can be made. As all of you are aware, you can make very sweet Kool Aid and less sweet Kool Aid.

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when 10 moles of sodium reacts with excess oxygen for 60 minutes, only 3 moles of sodium remains in 1000 millimeters of H20. Wha

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3 years ago

A battery can provide a current of 4.60 A at 3.40 V for 2.50 hr. How much energy (in kJ) is produced? 1st attempt kJ Energy

Lunna [17]

Answer:

The energy produced equals 140.760 kJ

Explanation:

The relation between power, current and voltage is

$Power=Current\times Voltage$

Applying the given values in the relation above we get

$Power=4.60\times 3.40=15.64W$

Now Since $Power=\frac{Energy}{Time}\\\\Energy=Power\times Time$

Again applying the calculated values we get

$Energy=15.64\times 2.50\times 3600=140760Joules=140.76kJ$

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3 years ago

What would be needed for shale to form from slate

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3 years ago

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3 years ago

What is the mass of a sample of metal that is heated from 58.8°C to 88.9°C with a

Vadim26 [7]

Answer:

$\boxed {\boxed {\sf 333 \ grams}}$

Explanation:

We are asked to find the mass of a sample of metal. We are given temperatures, specific heat, and joules of heat, so we will use the following formula.

$Q= mc \Delta T$

The heat added is 4500.0 Joules. The mass of the sample is unknown. The specific heat is 0.4494 Joules per gram degree Celsius. The difference in temperature is found by subtracting the initial temperature from the final temperature.

ΔT= final temperature - initial temperature

The sample was heated from 58.8 degrees Celsius to 88.9 degrees Celsius.

ΔT= 88.9 °C - 58.8 °C = 30.1 °C

Now we know three variables:

Q= 4500.0 J
c= 0.4494 J/g°C
ΔT = 30.1 °C

Substitute these values into the formula.

$4500.0 \ J = m (0.4494 \ J/g \textdegree C)(30.1 \textdegree C)$

Multiply on the right side of the equation. The units of degrees Celsius cancel.

$4500.0 \ J = m (13.52694 J/g)$

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 13.52694 Joules per gram. The inverse operation of multiplication is division, so we divide both sides by 13.52694 J/g

$\frac {4500.0 \ J }{13.52694 J/g}= \frac{m (13.52694 J/g)}{13.52694 J/g}$

The units of Joules cancel.

$\frac {4500.0 \ J }{13.52694 J/g}= m$

$332.6694729 \ g =m$

The original measurements have 5,4, and 3 significant figures. Our answer must have the least number or 3. For the number we found, that is the ones place. The 6 in the tenth place tells us to round the 2 up to a 3.

$333 \ g \approx m$

The mass of the sample of metal is approximately 333 grams.

8 0

2 years ago

What is the solution and solvent in Kool-Aid?​

What is the solution and solvent in Kool-Aid?