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Andrei [34K]
3 years ago
14

HELP WILL GIVE BRAINLIEST!!!!!!

Mathematics
1 answer:
aivan3 [116]3 years ago
5 0

Answer:

$130

Step-by-step explanation:

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How many people live in the state of Tennessee?
DochEvi [55]
6.549 million in 2014 i hope this helps.
8 0
3 years ago
Read 2 more answers
A shopkeeper buys a dress for $40
DanielleElmas [232]

Answer:

48 - 40 = $8, there is a $8 dollar increase.

Formula for change of percentage;

changed price

___________ x 100% (100/100)

original amount

Replace those values with the values we found;

40/48 x 100/100 = 20% increase.

4 0
2 years ago
A collection of nickels and quarters is worth 2.85 . There are 3 more nickels than quarters how many nickels and quarters are th
Zolol [24]

A nickel is equal to 5 cents or 0.05 dollars.

A quarter is equal to 25 cents or 0.25 dollars.

Let number of nickels be = n

Let number of quarters be = q

0.05n+0.25q=2.85    ...........(1)

As it is given, there are 3 more nickels than quarters so equation becomes,

n=q+3   ................(2)

Plug in the value of 'n' from (2) in (1)

0.05(q+3)+0.25q=2.85

= 0.05q+0.15+0.25q=2.85

0.30q=2.70

q=9

As n=q+3 we get, n=9+3=12

Hence, there are 12 nickels and 9 quarters.

3 0
3 years ago
Determine the factors of the expression x^2 - 9
Anuta_ua [19.1K]

Answer:

Step-by-step explanation:


The answer is B.


Use the sum-product pattern


2+3−3−9



Common factor from the two pairs


2+3−3−9x2+3x−3x−9


(+3)−3(+3)

Rewrite in factored form


(+3)−3(+3)


Solution:

(−3)(+3)

‘Hope it Helps!

5 0
2 years ago
There are 15 students in the 8th grade. The students are randomly placed into three different algebra classes of 5 students each
xeze [42]

Answer:

The probability is   \frac{6}{91} ≅ 0.0659

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And  also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is 1

Then for Terry there are 4 places out of 14 that puts Terry in the Evan's class.

We write 1.\frac{4}{14}

Finally for Trevor there are 3 places out of the remaining 13 that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}

The probability of the event is \frac{6}{91} ≅ 0.0659

5 0
4 years ago
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