Answer:
x=2 and y= -3
Step-by-step explanation:
This is a simultaneous equation. To solve this type of equation, there are three methods; substitution, Elimination and Graphical.
But here, we would be using the substitution method.
3x-y=9 Equation 1
2x-y=7. Equation 2
Getting y from equation 2, we have
-y= 7-2x
Multiply both sides by -
y= 2x-7 Equation 3
Substituting y for 2x-7 in equation 1, we have
3x- (2x-7)=9
3x-2x+7=9
x+7=9
x=9-7
x=2
Substituting x as 2 in equation 3
y=2x-7
y= 2(2)-7
y= 4-7
y= -3
Answer:
the answer is 325 you had to divide 650 by 2 which equals325
Answer:
Option 3x+5y=29 and -3x-12y=-48 is the system of equations equivalent to the given system of equations 3x+5y=29 and x+4y=16
Step-by-step explanation:
Given system of equations is 3x+5y=29 and x+4y=16
To find the equivalent system of equations to the given system of equations :
Option 3x+5y=29 and -3x-12y=-48 is the system of equations represents the given system of equations.
Because we can write the given equations as below
3x+5y=29 and x+4y=16
x+4y=16 rewritting as below
When multiply the above equation into (-3) we get
as same as the equation x+4y=16 so we can say that they are equivalent
Therefore Option 3x+5y=29 and -3x-12y=-48 is the system of equations represents the given system of equations
Therefore 3x+5y=29 and -3x-12y=-48 is the system of equations equivalent to the given system of equations 3x+5y=29 and x+4y=16
Answer: P/6
I hope this helps!
<span>The equation of a circle with center C=(h,k) and radius r is:
(x-h)^2+(y-k)^2=r^2
In this case the center is the point C=(a,b)=(h,k)→h=a, k=b, then:
(x-a)^2+(y-b)^2=r^2
We can apply the Pythagorean Theorem to find the distance between any point of the circle P=(x,y) and the Center C=(a,b). This distance must be equal to the radius of the circle:
A^2+B^2=C^2, where A and B are the legs of the triangle and C is the hypothenuse.
In this case, according with the figure: The legs of the triangle are:
A=x-a
B=y-b
And the hypothnuse C=r
Then replacing in the Pythagorean Theorem:
(x-a)^2+(y-b)^2=r^2
Equal to the equation of the circle </span>(x-a)^2+(y-b)^2=r^2
