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Alika [10]
3 years ago
13

How do I work out -5(-8)

Mathematics
2 answers:
slava [35]3 years ago
5 0
You have to simplify like this (-5)(-8)=40
arlik [135]3 years ago
4 0
When you have 2 negatives, it eaquals a positive so you can just take off both of the negatives and multiply 5 and 8, ,or, (-5)(-8)
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Solve the following: - 3 raised to 1 by 5 the whole raised to 4 (3^1/5)^4
Diano4ka-milaya [45]

Answer:

8.30256

Step-by-step explanation:

Step 1: Write out expression

((-3)^{\frac{1}{5} })^{4(3^{\frac{1}{5} })^4

Step 2: Use BPEMDAS to evaluate

(-1.24573)^{4(3^{\frac{1}{5} })^4

(-1.24573)^{4(1.24573)^4

(-1.24573)^{4(2.40822)

(-1.24573)^{9.6329}

= 8.30256

And we have our answer!

8 0
3 years ago
What is the circumference of a circle if the radius is 50 ?
Zina [86]
The appropriate formula is C = 2*pi*r.  

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3 years ago
Find the equation of the straight line passing through the point (3, 5)
Ne4ueva [31]

Answer:

y = -1/3x + 6

Step-by-step explanation:

the slope is -1/3 because you find the the reciprocal and switch the sign. To find the y intercept you plug in the points to the equation.

5 = -1/3(3) + b

5 = -1 + b

6 = b

5 0
3 years ago
Tyler goes running every 6 days. Steve goes running every 9 days. If they both ran today, in how many days will they run togethe
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sp2606 [1]

\displaystyle\\Answer:\ x=\sqrt{2}\ \ \ \ \ x=-\sqrt{2}\ \ \ \ \ x=\frac{ln5}{2}

Step-by-step explanation:

5x^2-x^2e^{2x}+2e^{2x}=10

Let:\ x^2=t  \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}

<em>Prologarithmize both parts of the equation:</em>

ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\

<u><em> Divide both parts of the equation by 2:</em></u>

\displaystyle\\x=\frac{ln5}{2}

t-2=0\\t-2+2=0+2\\t=2\\x^2=2\\x=\sqrt{2} \\x=-\sqrt{2}

6 0
1 year ago
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