F(x)=3x^2-5 when x=-11
f(-11)=3(-11)^2-5
f(-11)=-33^2-5
f(-11)=1089-5
f(-11)= 1084
Hope this could help!
Standard Form : f (x) = a(x - h)2 + k
Where in this equation (H,K) is the vortex of the parabola
<u>and there are four other ways to solving these quadratic</u>
1. Factoring
2. Completing the square
3. Your quadratic formula ( f (x) = a(x - h)2 + k )
4. Graphing
Answer: +23
Step-by-step explanation:
It would be 23 because the difference between -19 and 4 is 23
Answer:
Rate of change = 4,06 f/min
Step-by-step explanation:
The ascendent length 28 9/10 = 289/ 10
The time for that ascendent maneuver is total time 17 1/8 minutes - spended time in the elevation 10 minutes, then
17 1/8 = 137/8
137/8 - 10 = ( 137 - 80 ) /8 = 57/8 minutes
The rate of change in the diver´s elevation is
289 / 10 / 57/8
Rate of change = 289*8/ 57*10
Rate of change = 2312 / 570 ft/min
Rate of change = 4,06 f/min
Answer:
75.02 ft
Step-by-step explanation:
Split the problem into 2 different part. The bottom part of the tree is 5 feet because that's where your eye levels are, so you just have to solve the top part of the tree.
The top part of the tree is solved by finding the height of the triangle. If you remember SohCahToa, the opposite side of the angle is solved using tangent.
tan(angle) = opposite/adjacent
tan(35) = x/100, x is just the unknown height of the tree.
multiply 100 on both side to get x by itself.
x = 100tan(35)
x = 70.02
add that top height of the tree(70.02ft) with the bottom height of the tree(5ft).
70.02+5 = 75.02 ft