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3 years ago

Find The sun of 2-3+9/2-27/4+.....-177147/1024

1 answer:

4 0

Hello,

$s=2-3+ \dfrac{9}{2} - \dfrac{27}{4} +...- \dfrac{177147}{1024} \\\\

=2(1- \dfrac{3}{2} + \dfrac{3^2}{2^2} - \dfrac{3^3}{2^3}+...- \dfrac{3^{11}}{2^{11}} )\\\\
=2( \dfrac{1- (\dfrac{-3}{2})^{12}}{1+ \dfrac{3}{2} } )\\\\

=2( \dfrac{2^{12}-3^{12}}{ \dfrac{5}{2} } )\\\\

= \dfrac{4}{5*4096} *(-527345)=-102,9970703125$

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3 years ago

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ivanzaharov [21]

The simplification form of the provided expression is x¹⁸a³b³ option

(d) x¹⁸a³b³ is correct.

<h3>What is an integer exponent?</h3>

In mathematics, integer exponents are exponents that should be integers. It may be a positive or negative number. In this situation, the positive integer exponents determine the number of times the base number should be multiplied by itself.

It is given that:

The expression:

$= \rm (\dfrac{x^4a^2b^3}{x^{-2}ab^2})^3$

After using the integer exponent property:

$\rm =\dfrac{x^{12}a^6b^9x^6}{a^3b^6}$

= a³b³x¹⁸ Or

=x¹⁸a³b³

Thus, the simplification form of the provided expression is x¹⁸a³b³ option

(d) x¹⁸a³b³ is correct.

Learn more about the integer exponent here:

brainly.com/question/4533599

#SPJ1

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2 years ago