You'll actually need to graph for the first segment
but the second part can be solved with algebra
The equation of the line is y(x)=-x
if we test the co0ordinates we can find if the point lies on the line
(5,5)
y(x)=-x
Using the x co-ordinate
y(5)= -5
y=-5
Leaving us with (5,-5)
Because (5,-5) is not (5,5)
This is not a point on the line
The slope of the line is -1
Answer: The value of g(x) is x+3.
Step-by-step explanation:
Since we have given that

Here,

We need to find the value of g(x):

Hence, the value of g(x) is x+3.
7+5= 12 ones. Or one ten and 2 ones. They made 12.
Answer:
C)infinitely many solutions
Step-by-step explanation:
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Answer:


Step-by-step explanation:
<h3><u>Question 6</u></h3>
To find the greatest common factor (GCF), first list the prime factors of each number:
- 42 = 2 × 3 × 7
- 60 = 2 × 2 × 3 × 5
42 and 60 share one 2 and one 3 in common.
Multiply them together to get the GCF: 2 × 3 = 6.
Therefore, 6 is the GCF of 42 and 60.
Divide the numerator and the denominator by the found GCF:

<h3><u>Question 7</u></h3>
To find the greatest common factor (GCF), first list the prime factors of each number:
- 80 = 2 × 2 × 2 × 2 × 5
- 272 = 2 × 2 × 2 × 2 × 17
80 and 272 share four 2s in common.
Multiply them together to get the GCF: 2 × 2 × 2 × 2 = 16.
Therefore, 16 is the GCF of 80 and 272.
Divide the numerator and the denominator by the found GCF:
