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3 years ago

If you fill this out 20 points, but I need all the answers

Chemistry

1 answer:

Rashid [163]3 years ago

6 0

Answer:

Li 3 7 3 4 3

P 15 31 15 16 15

Cl 17 35 17 18 17

Ni 28 59 28 31 28

Ne 10 39 10 29 10

Ag 47 108 47 61 47

H 1 1 1 0 1

Si 14 28 14 14 14

W 74 184 74 110 74

Ne 10 20 10 10 10

Explanation:

Atomic number and the number of protons are the SAME

number of protons are electrons are the SAME

mass #- protons = Neutrons

Neutrons- mass #= protons

I HAVEN'T DONE THIS IN A WHILE SO I HOPE EVERYTHING IS CORRECT

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Eddi Din [679]

CHA is not an example of a molecule because there is no element represented by “A”

6 0

2 years ago

Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti

gayaneshka [121]

Answer : The value of $K$ for this reaction is, $2.6\times 10^{15}$

Explanation :

The given chemical reaction is:

$CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)$

Now we have to calculate value of $(\Delta G^o)$ .

$\Delta G^o=G_f_{product}-G_f_{reactant}$

$\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]$

where,

$\Delta G^o$ = Gibbs free energy of reaction = ?

n = number of moles

$\Delta G^0_{(HCH_3CO_2(g))}$ = -389.8 kJ/mol

$\Delta G^0_{(CH_3OH(g))}$ = -161.96 kJ/mol

$\Delta G^0_{(CO(g))}$ = -137.2 kJ/mol

Now put all the given values in this expression, we get:

$\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]$

$\Delta G^o=-89.4kJ/mol$

The relation between the equilibrium constant and standard Gibbs, free energy is:

$\Delta G^o=-RT\times \ln K$

where,

$\Delta G^o$ = standard Gibbs, free energy = -89.4 kJ/mol = -89400 J/mol

R = gas constant = 8.314 J/L.atm

T = temperature = $30.0^oC=273+30.0=303K$

$K$ = equilibrium constant = ?

Now put all the given values in this expression, we get:

$-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K$

$K=2.6\times 10^{15}$

Thus, the value of $K$ for this reaction is, $2.6\times 10^{15}$

4 0

3 years ago

por favor es urgente!!!!!!!!.... 1 -¿cuántos átomos- gramos de cloro hay en 88,75 g de dicho elemento? 2-¿calcular los moles de

Mamont248 [21]

Answer:

don't understand your language

6 0

2 years ago

DDT, an insecticide harmful to fish, birds, and humans, is produced by the following reaction. 2 C6H5Cl + C2HOCl3 → C14H9Cl5 + H

Elena-2011 [213]

Answer:

1,070.41 grams of DDT will be formed .Explanation:

1) $2 C_6H_5Cl + C_2HOCl_3\rightarrow C_{14}H_9Cl_5 + H_2O$

Moles of chlorobenzene = $\frac{1197 g}{112.5 g/mol}=10.64 mol$

According to reaction, 2 moles of chloro benzene reacts with 1 mole of chloral . Then 10.64 moles of chloro benzene will react with :

$\frac{1}{2}\times 10.64 mol=5.32 mole$ of chloral

2) Moles of chloral = $\frac{456 g}{147.5 g/mol}=3.0915 mol$

According to reaction, 1 moles of chloral reacts with 2 mole of chlorobenzene . Then 3.0915 moles of chloral will react with :

$\frac{2}{1}\times 3.0915 mol=6.1830 mol$ of chloro benzene

As we can see that chloral is in limiting amount and chloro benzene is in excessive amount. So, amount of DDT will depend upon amount of chloral.

According to reaction, 1 mole chloral gives 1 mole DDT.Then 3.0195 moles of chloral will give :

$\frac{1}{1}\times 3.0195 mol=3.0195 mol$

Mass of 3.0195 moles of DTT :

3.0195 mol × 354.5 g/mol = 1,070.41 g

1,070.41 grams of DDT will be formed .

3 0

3 years ago

PLZ HELP CHEMISTRY SUCKS BRO

uranmaximum [27]

Answer:

just click any of the buttons

6 0

2 years ago

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