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leva [86]
3 years ago
8

If you fill this out 20 points, but I need all the answers

Chemistry
1 answer:
Rashid [163]3 years ago
6 0

Answer:

Li   3   7   3   4   3

P   15   31   15   16   15

Cl   17   35   17   18   17

Ni   28   59   28   31   28

Ne   10   39   10   29   10

Ag   47   108   47   61   47

H   1   1   1   0   1

Si   14   28   14   14   14  

W   74   184   74   110   74

Ne   10   20   10   10    10

Explanation:

Atomic number and the number of protons are the SAME

number of protons are electrons are the SAME

mass #- protons = Neutrons

Neutrons- mass #= protons

I HAVEN'T DONE THIS IN A WHILE SO I HOPE EVERYTHING IS CORRECT

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Answer:

A

Explanation:

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What is the name of the state when electrons absorb energy and move to a higher energy level?
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A 0.4272 g sample of an element contains 2.241 x 10 ^21 atoms . what is the symbol of the element?
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Answer:

Likely \rm In (indium.)

Explanation:

Number of atoms: N = 2.241 \times 10^{21}.

Dividing, N, the number of atoms by the Avogadro constant, N_A \approx 6.023 \times 10^{23} \; \rm mol^{-1}, would give the number of moles of atoms in this sample:

\begin{aligned} n &= \frac{N}{N_{A}} \\ &\approx \frac{2.241 \times 10^{21}}{6.023 \times 10^{23}\; \rm mol^{-1}} \approx 3.72 \times 10^{-3}\; \rm mol \end{aligned}.

The mass of that many atom is m = 0.4272\; \rm g. Estimate the average mass of one mole of atoms in this sample:

\begin{aligned}M &= \frac{m}{n} \\ &\approx \frac{0.4272\; \rm g}{3.72 \times 10^{-3}\; \rm mol} \approx 114.82\; \rm g \cdot mol^{-1}\end{aligned}.

The average mass of one mole of atoms of an element (114.82\; \rm g \cdot mol^{-1} in this example) is numerically equal to the average atomic mass of that element. Refer to a modern periodic table and look for the element with average atomic mass 114.82. Indium, \rm In, is the closest match.

5 0
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