We are given that the
operation of all circuits is independent with each other, therefore we can use
the multiplication rule for independent events, which states that P (intersection
of A and B) = P(A) * P(B). In this case, we want the intersection of circuit 1 to
be working with the intersection of circuit 2 on and on until circuit 40. That
is, we want every circuit to work with each other. The given probability that
circuit 1 works is .99. The probability that circuit 2 works is still .99 since
this is independent events. And we see that the probability for each of the 40
circuit to work is .99. <span>
So P (intersection of 1 through 40) = .99 * .99 *
.99.....*.99 = (.99)^40 = .6689717586</span>
Answer:
<span>There is a 0.67 probability
(or 67%) that the product will work.</span>
Answer:
Step-by-step explanation:
Its not the best drawing but here
median 37
minimum 29
maximum 41
first quartile 33
third quartile 40
IQR 7
Answer:
Step-by-step explanation:
You can either substitute (8, 3) into both equations as a test, or you can find the solution yourself.
Rewrite
- x + 4y = 4
- x + 3y = 1
as
- x + 4y = 4
+ x - 3y = -1
and combine like terms. The result is y = 3. Then -x + 4(3) = 4, or 8 = x.
Yes, (8, 3) is a solution of this SYSTEM.
Answer:
x=½
y=5
Step-by-step explanation:
(8x+7y=39)2
16x+14y=78
<u>4</u><u>x</u><u>-</u><u>1</u><u>4</u><u>y</u><u>=</u><u>-</u><u>6</u><u>8</u> add the two equations
20x=10.
divide both sides by 20
x=½
8x+7y=39
4+7y=39
7y=39-4
7y=35
y=5
Answer:
x5]23/d%34)b=425xy
Step-by-step explanation:
