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3 years ago

Rebecca already knew 1 appetizer recipe before starting culinary school, and she will learn 3

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

5 0

Answer:

14 weeks

Step-by-step explanation:

so from what we know she already learned one appetizer recipe so she needs to learn 42 more so what we need to do since it's three every week we need to multiply three until we are able to get 42 so three times 14 gets 42 so that means that the answer would be 14

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Convert from general form to standard form x^2 + 4y^2 + 6x-40y+9 =0

Burka [1]

$x^2 + 4y^2 + 6x-40y+9 =0\\x^2 + 6x+9+4y^2-40y=0\\x^2+6x+9+4y^2-40y+100-100=0\\(x+3)^2+(2y-10)^2=100$

P.S. Hello from Russia

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3 years ago

What is the y-intercept of f (x) = 3.4’x?

klasskru [66]

Answer:

Step-by-step explanation:

Y intercept when x = 0

F(0) = 3 * 4^(0) = 3 * 1 = 3

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2 years ago

Find the slope of the line through the points (6,16) and (−6,4)

MakcuM [25]

$m = \frac{y2-y1}{x2-x1}$

$m = \frac{4-16}{-6-6} \\m = \frac{-12}{-12} \\\\m = 1$

Therefore, the slope of the line is 1. In case if you want to know the equation.

$y=mx+b\\y=x+b\\4=-6+b\\4+6=b\\10=b\\$

Therefore, the equation is y=x+10 by substituting the (-6,4) or we can substitute (6,16) too.

$y=mx+b\\y=x+b\\16=6+b\\16-6=b\\10=b\\$

It's the same, you can use any orders given.

Overall, the slope is 1 and the equation is y=x+10

3 0

3 years ago

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

7 0

3 years ago

Nikhil, Davina and Sid share a tin of celebrations amongst themselves in the ratio of 8:12:20 respectively.

Sav [38]

Answer:

160

Step-by-step explanation:

n : d : s

8 : 12 : 20

davina = 48 sweets

48/12 = 4

8 + 12 + 20 = 40

40 x 4 = 160 sweets total

5 0

3 years ago