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umka21 [38]
3 years ago
5

11. When you multiply two decimals less than 1, how does the product compare to the factors?

Mathematics
1 answer:
ANEK [815]3 years ago
5 0

Answer:

The product is usually smaller than the two numbers multiplied

Step-by-step explanation:

When we multiply two decimals less than one, it is a certainty that the result of the multiplication would be less than the two decimals that were multiplied. An example is the multiplication of the decimals below;

0.958 * 0.325

which equals 0.31135

We can see from the example above that the result of the multiplication of the two decimals that are less than one, results in a product that is less than the factors that were multiplied.

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Suppose an economy experiences an increase in unemployment across all industries. What is the result of this increase in unemplo
Nastasia [14]

Production would take place at a point inside the production possibility frontier

The Production possibilities curve is a curve that shows the various combination of two goods a company can produce when all its resources are fully utilised.  

The PPC is concave to the origin. This means that as more quantities of a product is produced, the fewer resources it has available to produce another good. As a result, less of the other product would be produced. So, the opportunity cost of producing a good increase as more and more of that good is produced.

Points inside the production possibilities curve means that the nations resources are not being fully utilised

When the unemployment rate increases, it means that labour resources are not been fully utilized. As a result, production would take place at point inside the production possibilities curve

Point outside the curve or to the right of the curve means that the production level is not attainable given the level of resources

Learn more about the production possibility curve here : brainly.com/question/12047178?referrer=searchResults

6 0
2 years ago
I AM STRUGGLING!!! PLEASE HELP ME!!
Butoxors [25]

Answer:

The answer would b 6.59 inches

4 0
2 years ago
Please help solve this system of equations
stepan [7]

Make a substitution:

\begin{cases}u=2x+y\\v=2x-y\end{cases}

Then the system becomes

\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}

Simplifying the equations gives

\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}

which is to say,

\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}

\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81

\implies\dfrac uv=\pm27

\implies u=\pm27v

Substituting this into the new system gives

\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1

\implies u=\pm27

Then

\begin{cases}x=\dfrac{u+v}4\\\\y=\dfrac{u-v}2}\end{cases}\implies x=\pm7,y=\pm13

(meaning two solutions are (7, 13) and (-7, -13))

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3 years ago
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vesna_86 [32]

Answer:

The answer is D

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