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3 years ago

10

What’s 94 divided by 33

2 answers:

nignag [31]3 years ago

8 0

94 divided by 33 is 2.8484848484848

Finger [1]3 years ago

6 0

It Equals 2.84848485

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The first term of geometric sequence is 7 and the common ratio is -2. Find the 9th term.

kobusy [5.1K]

$a_{1}$ = 7.

Ratio means multiply/divide.
To get the next number, multiply number by common ratio.
To get a previous number, divide by common ratio.

Since we want the next number...
2nd term: 7 x -2 = -14
3rd term: -14 x -2 = 28
4th term: 28 x -2 = -56
5th term: -56 x -2 = 112

Keep going until 9th term!

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3 years ago

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3 years ago

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Ann [662]

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3 years ago

Differentiate the following functions (x^3+1)(x-2)÷x^2

Masja [62]

Given:

The given function is:

$\dfrac{(x^3+1)(x-2)}{x^2}$

To find:

The differentiation of the given function.

Solution:

Consider the given function,

$y=\dfrac{(x^3+1)(x-2)}{x^2}$

It can be written as:

$y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}$

$y=\dfrac{x^4-2x^3+x-2}{x^2}$

$y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}$

$y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}$

Differentiate with respect to x.

$y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})$

$y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})$

$y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$

Therefore, the differentiation of the given function is $2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$ .

8 0

3 years ago