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sesenic [268]
3 years ago
10

What’s 94 divided by 33

Mathematics
2 answers:
nignag [31]3 years ago
8 0
94 divided by 33 is 2.8484848484848
Finger [1]3 years ago
6 0
It Equals 2.84848485
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The correct answer is D
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Instructions: Use a graphing calculator to approximate the zeros and vertex of the following quadratic functions. Round to one d
Juli2301 [7.4K]

Using a graphing calculator, we can see the graph of the function y = x²-4x+1:

as we can see, the vertex of the function is (2,-3), and the solutions are (0.3,0) and (3.7,0)

4 0
1 year ago
Draw three lines that are parallel to the x-axis. Read the ordered pairs for points on each line. What generalization can you ma
irina [24]

Answer:

If the line is parallel to the x-axis than only x value changes and y value remains constant.

Step-by-step explanation:

Consider the provided information.

We need to draw three lines that are parallel to the x-axis.

The required graph is shown below:

Now the ordered pairs for points on each line is:

For line y=-3 The ordered pairs are (-1,-3), (0,-3) and (1,-3)

For line y=2 The ordered pairs are (-2,2), (2,2) and (3,2)

For line y=4 The ordered pairs are (-3,4), (0,4) and (4,4)

Here we can observe the x value changes but y values remains constant.

Therefore, if the line is parallel to the x-axis than only x value changes and y value remains constant.

7 0
3 years ago
h(x) = x ^ 2 - 7x - 8 1) What are the zeros of the function? Write the smaller first, and the larger second smaller I largerx =
kramer

Answer:

The zeros are x = -1 and x = 8

The vertex is (3.5, -20.25)

Step-by-step explanation:

When we have a quadratic equation like:

y = a*x^2 + b*x + c

The zeros of the function are the values of x such that:

a*x^2 + b*x + c = 0

And the solutions are given by the Bhaskara's equation, which is:

x = \frac{-b \pm \sqrt{b^2 - 4*a*c} }{2*a}

And the vertex is at:

x = -b/2a

The y-value at the vertex is the function evaluated in that point.

In this case, we have the equation:

h(x) = x^2 - 7*x - 8

Then:

a = 1

b = -7

c= -8

Replacing these in the Bhaskara's equation we get:

x = \frac{-(-7)  \pm \sqrt{(-7)^2-4*1*(-8)} }{2*1} = \frac{7   \pm 9 }{2}

Then the two solutions are:

x = (7 - 9)/2 = -2/2 = -1   (this is the smaller one)

and

x = (7 + 9)/2 = 16/2 = 8  (this is the larger one)

And we will have the vertex at:

x = -(-7)/2*1 = 7/2 = 3.5

Evaluating h(x) in 3.5 we get:

h(3.5) = (3.5)^2 - 7*(3.5) - 8 = -20.25

Then the vertex is the point:

(3.5, -20.25)

5 0
3 years ago
Simplify the expression. Please help, really stuck!!
andrew11 [14]
(-2y + 5 ) ( y+3) 
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4 years ago
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