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Dennis_Churaev [7]
3 years ago
5

3. (07.04)

Mathematics
1 answer:
Naddik [55]3 years ago
5 0

Answer:

The probability  that an applicant does not get a job if he or she has an interview is 20%.

Step-by-step explanation:

  • If the applicant has been interviewed, then she/he belongs to the group of 20 people that had an interview.
  • 16 of the 20 people who were interviewed were offered a job, which means that 4 of the 20 people interviewed were not offered a job.
  • Then, 4/20= 20% of the people who were intervied did not get a job, which means that the <u>probability that an applicant does not get a job if he/she were interviewed is 20%</u>.
  • Pat attention: this probability results from analysing the probability of getting a job once you have had an interview (this condition restricts our attention to the group of 20 people who had an interview, and not to the hole group of 500 people who did apply for the job).
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Answer:

a. The mean refractory period= 1.85 and the standard error = 0.06455

b.  90% confidence interval for the mean absolute refractory period for all mice when subjected to the same treatment = 1.6981, 2.0019

c. Yes, the data give good evidence to support this theory

Step-by-step explanation:

a.  The table below shows the calculations:

                 X                (X-mean)^2

                1.7             0.0225

                1.8                 0.0025

                1.9                 0.0025

                2.0                 0.0225

Total        7.4                  0.05

Sample size: n=4

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b. Degree of freedom: df = n-1 = 3

Critical value of t for 90% confidence interval is: 2.3534

The confidence interval is  \bar{x}\pm t_{c}se = 1.85\pm 2.3534\cdot 0.06455=1.85\pm 0.1519 = (1.6981, 2.0019)

c. The Hypotheses are:

H_{0}:\mu=1.3,H_{1}:\mu>1.3

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t=\frac{\bar{x}-\mu}{s/\sqrt{n}}=8.52

The p-value is: 0.0017

We reject the null hypothesis because p-value is less than 0.05 . This indicates that the data gave good evidence to support this theory.

4 0
3 years ago
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