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erica [24]
2 years ago
11

You select a marble from a jar. You know that

Mathematics
1 answer:
leva [86]2 years ago
4 0

Answer:

5/7

Step-by-step explanation:

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Can someone help me with this? I don’t understand it.
horrorfan [7]

Answer:

x+y=z

4+9=13

Step-by-step explanation:

x=4

2(4)+1=y=9

4+9=13

3 0
2 years ago
What is the value of the expression below when a = 5?<br> ​<br> ​ 7a - 4
Ostrovityanka [42]

Answer:

31

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Ruth wants to buy a skateboard for $56. She has $90 in her account. She spent $11.65 to buy stationary. She also wants to buy so
nevsk [136]
The answer is the second one I dont have that symbol on my keyboard but it’s the second answer on the multi choice
90-11.65-56=22.35
divide that by 3.72 u get 6 so she can only get six comics or any whole positive number lower than that. Therefore it’s #2
5 0
2 years ago
Read 2 more answers
Find the real numbers x and y if -3+ix^2y and x^2+y+4i are conjugate of each other. Pls solve with the steps
Firdavs [7]
ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work

EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same

For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y

For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4

Therefore, for the two expressions to be conjugates, we must satisfy the two conditions. 

Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the 

   x²y = -4 ... (I)

Condition 2: Real parts are the same

   x² + y = -3 ... (II)

We have a system of equations since both conditions must be satisfied

   x²y = -4 ... (I)
   x² + y = -3 ... (II)

We can rearrange equation (II) so that we have

   y = -3 - x² ... (II)

Substituting into equation (I)

   x²y = -4 ... (I)
   x²(-3 - x²) = -4
   -3x² - x⁴ = -4
   x⁴ + 3x² - 4 = 0
   (x² + 4)(x² - 1) = 0
   (x² + 4)(x-1)(x+1) = 0

Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.

Solve for y:

   y = -3 - x² ... (II)
   y = -3 - (±1)²
   y = -3 - 1
   y = -4

So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:

   -3 + ix²y 
   = -3 + i(±1)²(-4)
   = -3 - 4i

   x² + y + 4i
   = (±1)² - 4 + 4i
   = 1 - 4 + 4i
   = -3 + 4i

They result in conjugates
4 0
3 years ago
Read 2 more answers
Rolling a Red and Yellow Dice
grandymaker [24]

Answer:

Option C 5/12 is correct option

Step-by-step explanation:

We have to find the probability that shows yellow dice has a larger value than the red dice.

Probability= total no of favorable outcomes / total no of outcomes

in our case, considering the data set, we have to find those pair where value of yellow die is greater than the red die. Where (1,2) represents 1 on the red die and 2 on the yellow die

(1,2) (1,3) (1,4) (1,5) (1,6)

     (2,3) (2,4) (2,5) (2,6)

              (3,4) (3,5) (3,6)

                       (4,5) (4,6)

                                (5,6)

These are the possibilities where yellow die has greater value than red die.

total no of favorable outcomes = 15

total no of outcomes = 36

probability that yellow die has greater value than red die = 15 / 36

                                                                                                = 5/ 12

Option C 5/12 is correct option

3 0
2 years ago
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