Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
Step-by-step explanation:
Let q represent the number of quarters Theresa has. Then the value of her coins is ...
0.25q + 0.10(20 -q) = 2.75
0.15q = 0.75 . . . . . . . . . subtract 2.00, collect terms
q = 0.75/0.15 = 5
Theresa has 5 quarters and 15 dimes.
Answer:
10737418.24
Step-by-step explanation:
The answer is 2^n
Answer:
see the procedure
Step-by-step explanation:
Looking at the graph we have
The graph represent a vertical parabola open upward
The vertex is a minimum
The vertex is the point (-4,-3)
The domain is the interval -----> (-∞,∞)
The Domain is all real numbers
The range is the interval ----> [-3,∞)
The range is all real numbers greater than or equal to -3
The graph is increasing in the interval (-4,∞)
The graph is decreasing in the interval (-∞,-4)
The minimum of the graph is y=-3 occurs at x=-4
Answer:
y=-3/4x+3
Step-by-step explanation:
subtract 3x from both sides: 4y=-3x+12
Divide both sides by 4: y=-3/4y+3
