Answer:
second season
Step-by-step explanation:
5/9 ≈ 0.56 . . . first season
11/15 ≈ 0.73 . . second season
The greater fraction of field goals was made in the second season.
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You can also compare these fractions in this way:
{5/9, 11/15}
Multiply both by 9×15:*
{5·15, 9·11} = {75, 99}
The second fraction is larger.
_____
* The product of the denominators is the simplest number to compute as a multiple of both denominators. A smaller value can be found by removing a factor of 3, which is the GCD of 9 and 15. If both fractions are multiplied by 9×15/3 = 45, the result is {25, 33}. IMO, that's more work.
10 mark brainliest please
Answer:
222 small ones and 74 middle ones
Step-by-step explanation:
The computation is shown below:
Let us assume medium ones be x
so the small ones be 3x
And, the total is 296
So, the equation is
x + 3 x = 296
4x = 296
Medium ones = x = 74
And, the small ones is = 3 × 74
= 222
Answer:
<h3>FOR THIS PROBLEM I GOT..... (20/r)-(20/s)</h3>
Step-by-step explanation:
pls brainlest mee
Answer:
Total number of ways to distribute the prize = 2187
Step-by-step explanation:
Given:
Number of prizes = 7
Number of peoples = 3
We need to find the total number of ways to distribute the prize.
Solution:
From the above statement, 7 prizes are to be distributed between 3 people, wherein each person gets at least one prize.
Each prize is to be distributed among three persons. When the first prize is to be awarded, one of the three is chosen to win the prize. When the second prize is to be awarded, there are again three choices.
So, total number of distribution of the prizes is given as:
Therefore, total number of ways to distribute the prizes = 2187
