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Orlov [11]
3 years ago
8

Use pascal's triangle to find (8 4) I don't get how to do this can some one help me please!!

Mathematics
1 answer:
Olin [163]3 years ago
6 0
Pull out your reference sheet that has the Pascal's Triangle.

Step 1) Locate the row that starts with 1, 8, ... If this row isn't shown, then you'll need to find a bigger Pascal's Triangle. 

Step 2) Count out exactly five spaces starting at the first value 1. Why five? Because we start at 0 instead of starting at 1. The first value in the row represents 8 \choose 0 while the second value in that row represents 8 \choose 1 and the third value represents 8 \choose 2 and so on. So the value 8 \choose 4 is in the fifth slot from the left.

You should land on the value 70, which is the final answer
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I believe that the manatee can swim 5 miles per hour

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3 years ago
Please help I need this for a text ASAP.
Sladkaya [172]

The values of x and y are 45 and 8.

<h3>What is a Linear Pair of Angles?</h3>

When two lines meet at a single point, a pair of linear angles is created. If the angles follow the point where the two lines cross, they are considered to be linear. A linear pair's angles add up to 180° in every case.

Given:

Measures of two linear pairs of angles which are of equal measures are 2x and 11y + 2.

As the sum of linear pair of angles is 180°, and if they are of equal measures, each angle must be equal to 90°.

To determine the values of x and y we equate the given angles to 90°.

2x = 90°

⇒ x = 45

And 11y+2 = 90°

⇒ 11y = 90-2 = 88

⇒ y = 8

To know more about linear pairs visit:

brainly.com/question/17525542

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8 0
1 year ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
Which represents the solution set of an any quality 5X-9 greater than 21
Svet_ta [14]

Answer:

The last one

Step-by-step explanation:

5x<30

x<6

Because when you divide by pos+ number

the symbol cannot change.

6 0
3 years ago
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