Answer:
choice 4
triangle ABC is congruent to triangle DCB because of the Side-Side-Side congruency theorem
Step-by-step explanation:
Answer:
The probability that he selects a raisin bagel and then a plain bagel is
.
Step-by-step explanation:
Probability:
The ratio of the number of outcomes of favorable event to total number of all possible outcomes is called probability of the favorable event.

Given that, there are 4 blueberry, 6 raisins and 2 plain bangles in a bag.
Total number of bangles= (4+6+2)
= 12
The probability that he selects a raisin



Total number of remaining bagels is =(12-1)=11
After selecting a raisin bagel,the probability that he selects a plain bangle is


Selecting of a raisin bangle and a plain bangle are both independent event.
The probability that he selects a raisin bagel and then a plain bagel is


Answer:
the answer is 36ft by 48ft
Step-by-step explanation:
We first need to find the measurements of the green squares. Given the drawing is to scale we can say that each green square has equivalent measurements. Since there are 144 feet on each side of the original drawing, and 12 green squares on each side as well, then we need to divide 144 by 12 to find the measurements of one square. 144/12=12. the green squares are each 12ft by 12ft. to find the measurement of the jungle gym, we see how many green squares are on each side (there are 3 and 4) then multiply that number by 12. 4*12 I 48, and 3*12 is 36. Hence the measurements of 36ft by 48ft.
What is the question? I can't tell by the picture quality.
Answer:

Step-by-step explanation:
m∠4 + m∠7 = 180 (Adjacent Angles of a parallelogram)
<u>Given that</u> m∠4 = x + 45, m∠7 = x² + 45
x + 45 + x² + 45 = 180
x² + x + 90 = 180
x² + x = 180 - 90
x² + x = 90
x² + x - 90 = 0
Using mid-term break formula
x² + 10x - 9x - 90 = 0
x(x+10) - 9(x+10) = 0
(x - 9)(x + 10) = 0
<u>Either, </u>
x-9 = 0 <u>OR</u> x+10 = 0
x = 9 <u>OR</u> x = -10
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Now,
m < 7 = x² + 45
<u>For x = 9</u>
m < 7 = (9)² + 45
m < 7 = 81 + 45
<h3>m < 7 = 126°</h3>
<u>For x = -10</u>
m < 7 = (-10)² + 45
m < 7 = 100 + 45
<h3>m < 7 = 145°</h3>
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AnonymousHelper1807</h3>