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krok68 [10]
3 years ago
11

Could anybody give me some help? I'm a little confused .-. <3

Mathematics
1 answer:
nika2105 [10]3 years ago
3 0
What your teacher wants is for you to isolate y in the given equation. In other words, get y all by itself. 

To do this, you'll do two basic steps:
Step 1) Subtract 2x from both sides
Step 2) Divide both sides by 3

Let's do that and we get...
2x+3y = 1470
2x+3y-2x = 1470-2x ... apply step 1
3y = 1470-2x
3y = -2x+1470
3y/3 = (-2x+1470)/3 ... apply step 2 
y = (-2x)/3 + 1470/3
y = (-2/3)x + 490

After isolating y, we get y = (-2/3)x + 490
To get this into function notation, we simply replace y with f(x) to get the final answer f(x) = (-2/3)x+490 which is the same as writing f(x) = -\frac{2}{3}x+490

This graph represents all of the ordered pairs (x,y) that make the original equation true. For example, the point (x,y) = (0,490) is on the line where x = 0 and y = 490. This point is when 0 sandwiches are sold and 490 wraps are sold yielding a profit of $1470. Another point on this line is (x,y) = (3,488). Now 3 sandwiches have been sold along with 488 wraps leading to the same profit of $1470. Any ordered pair point you pick on the line should lead you to the same profit. 
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A manager recorded how many hours each of 11 cashiers worked in a week. Which interval contains the median number of hours worke
Lana71 [14]

Answer:

Step-by-step explanation:

Hello!

In descriptive statistics, the median is a measurement of center position. It separates the sample in halves. (bottom 50% from upper 50%)

The manager took a sample of 11 cashiers and recorded the worked hours in a week

To identify the median you have to calculate it's position:

The position is calculated as

PosMe= (n+1)/2= (11+1)/2= 6 cashier

This means that the Median of hours worked is a week observed corresponds to the 6th cashier (after ordering the data from lowest to highest)

If you observe the histogram, the x-axis corresponds to worked hours and the y-axis shows the number of workers.

The workers were already arranged from least hours worked to most hours worked.

The first interval corresponds to 0-10 worked hours and two workers recorded these working times.

The second interval corresponds to 10-20 worked hours and three workers recorded these working times.

In the third interval of 20-30 hours, no workers recorded these working times.

The fourth interval corresponds to 30 - 40 worked hours and 5 workers recorded these working times.

The fifth interval corresponds to 40 - 50 worked hours and only one worker recorded these working hours.

The first five workers were recorded in the first two intervals and the sixth worker was recorded in the fourth interval. So the interval that contains the median number of hours worked is "30 - 40 hours"

I hope this helps!

5 0
3 years ago
Graph the function f(x)=(x+1)(x-2)
creativ13 [48]
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6 0
3 years ago
The nth term of a sequence is 3n + 2
gavmur [86]

Answer:

see explanation

Step-by-step explanation:

To calculate the first 3 terms substitute n = 1, 2, 3 into the n th term rule

a_{1} = (3 × 1) + 2 = 3 + 2 = 5

a_{2} = (3 × 2) + 2 = 6 + 2 = 8

a_{3} = (3 × 3) + 2 = 9 + 2 = 11

------------------------------------------------------------------

substitute n = 10 into the n th term rule

a_{10} = (3 × 10) + 2 = 30 + 2 = 32

3 0
4 years ago
Read 2 more answers
0.48 divided by 0.06 with shown work please help!
Valentin [98]

Answer: 8

Step-by-step explanation:

2 To convert to a percent, multiply the decimal by 100.

8\times 100=800

8×100=800

800

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6 0
3 years ago
Of the 50 students in an undergraduate statistics class, 60% send email and/or text messages during any given lecture. They have
sasho [114]

Answer:

0.3 or 30%

Step-by-step explanation:

Since no innocent student will ever be caught, the probability that a student sends an email and/or text message during a lecture AND gets caught is given by the product of the probability of a student sending a message (60%) by the probability of the professor catching them (50%) :

P = 0.5*0.6 = 0.3

The probability is 0.3 or 30%.

7 0
3 years ago
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