Answers
1. X= -4
2. X=9
3. X= 15/4 or 3.75
4. X=2
Answer:
230 points
Step-by-step explanation:
46 / 0.20% = 230
9514 1404 393
Answer:
(c) 5y - x = -20
Step-by-step explanation:
When the x- and y-terms are on the same side of the equation, the slope of the line will be ...
m = -(coefficient of x)/(coefficient of y)
So, the slopes of the offered choices are ...
a) -5/1 = -5
b) -1/5
c) -(-1)/5 = 1/5 . . . . . parallel to given line
d) -5/-1 = 5
The lines will be parallel when their slopes are the same. The slope of the given line is the coefficient of x, 1/5. Choice C has the same slope.
Answer:
See below
Step-by-step explanation:
1: (b+1)*(3b)*(b-5)
(3b^2+3b)(b-5)
3b^3-15b^2+3b^2-10b
3b^3-12b^2-10b
2: πr^ 2(h/3)
π(n-2)^2(12n/3)
π(n-2)(n-2)(12n/3)
π(n^2-2n-2n+4)(12n/3)
π(n^2-4n+4)(12n/3)
π(n^2-4n+4)(4n)
π(4n^3-16n^2+16n)
<em>(I'm not 100% sure with this one)</em>
3: (lwh)/3
((k-2)(2k+3)(3k))/3
((2k^2-4k+3k-6)(3k))/3
(6k^3-12k^2+9k^2-18k)/3
(6k^3-3k^2-18k)/3
2k^3-k^2-6k
To solve this problem you must follow the proccedure below:
a<span>. Find the perimeter and area of the cracker remaining:
The perimeter of a quarter circle is:
P=(</span>πr/2)+2r
P=(πx3 cm/2)+2(3 cm)
P=10.71 cm
The perimeter of <span>the cracker remaining is:
</span><span>
Pt=3 cm+6 cm+3 cm+10.71 cm
Pt=22.71 cm
The area of a quarter circle is:
A=</span>πr²/4
A=π(3 cm)²/4
A=7.06 cm²
<span>
The area of</span><span>of the cracker remaining is:
</span><span>
At=Area of a square-Area of quarter circle
At=L</span>²-(πr²/4)
At=(6 cm)²-(π(3 cm)²/4)
At=28.93 cm²
<span>
b. About how many bites can you get from the entire cracker?</span>
Number of bites=L²/(π(3 cm)²/4)
Number of bites=5
