Two lines are perpendicular if and only if the product of their slopes is - 1.
So, you just need to find the slope of each line and find out the product of their slopes.
I will do one example for you.
L1: y = 3x + 5
L2: y = - 3x + 14
L3: y = -x/3 + 14
The slope of a line is the coefficient of the x.
So the slopes are:
L1: slope 3
L2: slope -3
L3: slope -1/3
So now multiply the slopes of each pair of lines:
L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular
L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular
L1 and L3: (3) * (-1/3) = -1 => Yes, they are penpendicular.
Answer:
Step-by-step explanation:
<u>OAmalOHopeO</u>
The scale factor is six and the dilation is an enlargement.
Answer: 43
Step-by-step explanation:
∠KLN and ∠MLI make up a pair of vertical angles.
Vertical angles share a vertex and are the opposite angles formed by intersecting lines. They are also congruent, but just because two angles are congruent doesn't mean they are vertical. That's why ∠KLN and ∠JIG are NOT vertical, for instance.
