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sashaice [31]
2 years ago
6

Write the exponent for 4^? = 64 What number is the question mark? *

Mathematics
1 answer:
Elden [556K]2 years ago
5 0
The ? Is 3

As 4^3 = 64

4x4x4= 64
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Please EXPLAIN
11111nata11111 [884]

Answer:

<u>The correct answer is 58 1/2 feet. See below to understand the difference of both methods.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the question using both methods:

Area of each student = 4 1/2 square feet

Number of students = 13

2. Let's use the first method to solve the question:

4 1/2 = 9/2 (Improper fraction because the numerator, 9 is bigger than the denominator, 2)

9/2 * 13 = 117/2

<u>117/2 = 58 1/2 square feet</u>

3. Let's use the second method to solve the question:

4 1/2 = 4 + 1/2 (Using addition to rewrite the fraction)

(4 + 1/2) * 13 = (4 * 13) + (1/2 * 13) (Distributive property of the multiplication)

(4 * 13) + (1/2 * 13) = 52 + 13/2 = 52 + 6 1/2

<u>52 + 6 1/2 = 58 1/2 square feet</u>

5 0
3 years ago
What is 625 x 625 Then what is the atomic weight of hydrogen.
Illusion [34]

Answer:

la respuesta es:

Step-by-step explanatio:

625 x 625

390,625

6 0
2 years ago
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
3x ×?=90 somebody help me please​
Galina-37 [17]

Answer:

30

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Determine which of these illustrates two quantities that combine to make 0.
Butoxors [25]
I think it’s gonna be D
6 0
3 years ago
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