Hi
5720 feet / minute
Here ulyou go mate
Answer:
0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean of 116 cm and a standard deviation of 5.4 cm.
This means that 
Find the probability that one selected subcomponent is longer than 118 cm.
This is 1 subtracted by the pvalue of Z when X = 118. So



has a pvalue of 0.6443
1 - 0.6443 = 0.3557
0.3557 = 35.57% probability that one selected subcomponent is longer than 118 cm.
0.5 will be rounded to 1.0
1.2 will be rounded to 1.0
1.7 will be rounded to 2.0
3.4 will be rounded to 3.0
1) additive inverse property is when an integer is added to its opposite integer (ex: -3 + 3)
2. Sorry I didn’t learn signed numbers yet :(((
3. Commutative property is when you change the order of numbers in the expression but associative property is when you are regrouping numbers in the expression.
4. Absolute value is the distance between an integer and 0. And yes you can solve distance problems and grid problems using absolute value.