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faust18 [17]
3 years ago
15

A park is 4.6 miles long and 2.7 miles wide. A:what is the total distance around the park? B:if a racecar drove 50 times around

the park, how far will it go?
Mathematics
1 answer:
Vlada [557]3 years ago
6 0

Answer:

A) Total distance around the park is 14.6 miles

B) The total distance drove by racer 730 miles

Step-by-step explanation:

Given as :

The length of park = 4.6 miles

The width of park = 2.7 miles

Let the total distance cover around park = Perimeter of park = P miles

So, Perimeter of rectangular park = 2 × Length + 2 × width

or, P = 2 × 4.6 + 2 × 2.7

I.e P = 9.2 + 5.4

Or, perimeter = 14.6 miles

A ) ∴ Total distance around the park = 14.6 miles

B ) The total distance drove by racer = 50 times around the park

  So, The total distance drove by car = 50 × Total distance around the park

∴The total distance drove by car = 50 × 14.6 = 730 miles

Hence A) Total distance around the park is 14.6 miles

          B) The total distance drove by racer 730 miles   answer                                                                              

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Which statement about the figure MUST be true? Select all that apply.
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<h2>○=> <u>Correct options</u> :</h2><h2>□\color{plum}\tt\bold{(C) \: SR = 27}</h2><h2>□\color{plum}\tt\bold{(D) \: QR = 54 }</h2><h3><u>Steps to derive the correct options</u> :</h3>

Since two sides and one included angle is equal in △PQS and △PRS, we can conclude that they are congruent under the SAS congruence criterion.

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▪︎Angle S = Angle S

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Given :

Measure of segment QS = 6n+3

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= \tt6n + 3 = 4n + 11

= \tt6n + 3 - 4n = 11

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=\tt 6n + 3

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\color{plum}\tt \: \bold{QS = 6n + 3 = \tt\bold{27}}

Thus, measure of QS = 27

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Measure of QR :

=\tt 27+27

\color{plum}\tt \: \bold{QR = 27+27 \tt\bold{=54}}

Thus :

▪︎QS = 27

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▪︎QR = 54

Therefore, the correct options are :

▪︎(C) SR = 27

▪︎(D) QR = 54

7 0
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