This appears to be about rules of exponents as much as anything. The applicable "definitions, identities, and properties" are
i^0 = 1 . . . . . as is true for any non-zero value to the zero power
i^1 = i . . . . . . as is true for any value to the first power
i^2 = -1 . . . . . from the definition of i
i^3 = -i . . . . . = (i^2)·(i^1) = -1·i = -i
i^n = i^(n mod 4) . . . . . where "n mod 4" is the remainder after division by 4
1. = -3^4·i^(3·2+0+2·4) = -81·i^14 =
812. = i^((3-5)·2+0 = i^-4 =
13. = -2^2·i^(4+2+2+(-1+1+5)·3+0) = -4·i^23 =
4i4. = i^(3+(2+3+4+0+2+5)·2) = i^35 =
-i
Answer:
Hi there!
Your answer is:
1050 liters per 6 days
Step-by-step explanation:
350liters per 2 days
*3 to determine 6 days
1050 liters per 6 days
Hope this helps
Answer:
11/1 or 11
Step-by-step explanation:
The scale of the y-axis is 11 and the scale of the x-axis is 1. As said before the Unit Rate is y/x
If you pick one point, let's say (2,22), that will give you 22/2. If we simplify that fraction you get 11/1 or 11.
Answer:
£11,904
Step-by-step explanation:
Simple interest = PRT/100 where P = initial investment, R = rate and T = time.
So interest on £9600 = 9600*8*3/ 100
= £2304
So the value after 3 years = 9600 + 2304
= £11,904 (answer)