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JulsSmile [24]
3 years ago
5

Please help this is due tomorrow

Mathematics
2 answers:
Lostsunrise [7]3 years ago
7 0

\sf \left(\dfrac{1}{7}\right)^3\ is\ basically\ like\ saying\ you're\ multiplying\ \dfrac{1}{7}\ by\ \dfrac{1}{7},\ three\ times.

\implies\ \sf \dfrac{1}{7}\ \times\ \dfrac{1}{7}\ \times\ \dfrac{1}{7}\\\\\\\implies\ \dfrac{1}{343}

Therefore, (1/7)³ = 1/343, implying that the answer is option (D).

Hope it helps. :)

Tasya [4]3 years ago
4 0

Answer:

D, 1/343

Step-by-step explanation:

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3 years ago
A farmer has a truckload of watermelons to take to market. At the beginning of the trip, the watermelons weigh 1000 kg. 99% of t
Mariulka [41]

Answer:

The weight of watermelon at the end of the trip is <u>500 kg.</u>

Step-by-step explanation:

Given:

The weight of watermelons is 1000kg.

At the beginning of the trip watermelon is 99% of the weight:

99% of 1000kg

\frac{99}{100}\times 1000

=0.99\times 1000

= 990 kg

Now, at the end of the trip it is 98% of weight. So, let x kg of water has been evaporated. So, remaining weight of the watermelon is 1000-x.

If x kg of water is removed, then the amount of water left is 990-x.

As per question, water now weighs 98% of the total weight. So,

98% of (1000-x) = 990-x

\frac{98}{100}\times (1000-x)=990-x

980-0.98x=990-x

-0.98x+x=990-980 (Bringing like terms on one side)

0.02x=10\\x=\frac{10}{0.02}=500\ kg

Therefore, the weight of watermelon at the end of the trip is given as:

Weight = 1000 - x = 1000 - 500 = 500 kg

Therefore, the watermelon weighs 500 kg at the end of trip.

7 0
3 years ago
Read 2 more answers
Parallel lines never intersect, therefore, there is one solution
anyanavicka [17]

Answer:

Step-by-step explanation:

If parallel lines don't intersect, then there can't be any solutions. An intersection represents a solution.

If this is a true false question, the statement is false.

6 0
3 years ago
Can anyone rewrite the quadratic function in standard form?
yulyashka [42]

Answer:

Step-by-step explanation:

y=3(x-3)(x-4)

=3(x²-4x-3x+12)

or y=3(x²-7x+12)

or y=3x²-21x+36

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3 years ago
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Two fair dice are tossed, and the up face on each die is recorded. Find the probability of observing each of the following event
Paladinen [302]

Answer:

Step-by-step explanation:

The sample space is shown in the attached photo.

Probability = number of favourable outcomes/total number of outcomes.

Looking at the diagram, the total possible outcomes is 36.

A) from the diagram, the total number of events in which the sum of the numbers is odd is 18. Therefore, the probability that the sum of the numbers is odd is

18/36 = 1/2

B) the total number of events in which the sum of the numbers is 10 or more is 6. Therefore, the probability that the sum of the numbers is 10 or more is

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C) the total number of events in which 3 appears on each of the two dice is 1. Therefore, the probability that 3 appears on each of the two dice is

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7 0
3 years ago
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