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jonny [76]
2 years ago
6

Dentify the pattern rule for this sequence: 1, 4, 2, 8, 6, 24, 22…

Mathematics
2 answers:
stepladder [879]2 years ago
7 0

Answer:

Step-by-step explanation:ffcrrer

steposvetlana [31]2 years ago
5 0

Answer:

multiply by 4 subtract 2

-hope this helped have a good rest of your day :)

Step-by-step explanation:

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A segment with endpoints (3,7) and (-8,7) is rotated around the origin. how long will the new segment be ?
amid [387]
11 units long.  When something is rotated it does not change its shape/length, only when it is dilated.
4 0
3 years ago
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The length of a rectangle is increasing at a rate of 6 cm/s and the width is increasing at a rate of 4 cm/s. when the length is
alukav5142 [94]
The area is 192 and the speed it’s increasing at is 24 cm^2/s
7 0
3 years ago
PLEASE HELP!! 25 POINTS This was already due and it's almost 1 AM-- I just need an explanation on one or all the answers if you
kirza4 [7]

Answer:

See below

Step-by-step explanation:

<em>Refer to attached</em>

34.

  • h(x) = 8 ⇒
  • x = 4 as per diagram

35.

  • g(8) = 4 as per table

36.

  • f(x) = 2 ⇒
  • x = -0.8 as per graph (approx.)

37.

  • f(2) = -2 as per graph

38.

  • h(-1) = -8 as per diagram

39.

  • g(x) = 4 ⇒
  • x = 9 or x = 8 as per table

6 0
3 years ago
at 6:00 a.m., the temperature is 58°. At 2:00 p.m., temperature is 76°. Find the rate of change in degrees per hour during this
lesya [120]

Answer:

The rate of change is of 2.25 degrees per hour.

Step-by-step explanation:

The rate of change in degrees per hour is given by by the change in temperature divided by the change in time(by number of hours).

In this question:

From 6 am to 2 pm, there are 12 - 6 + 2 - 0 = 6 + 2 = 8 hours

The change in temperature was of 76 - 58 = 18º

Rate of change:

18º/8 = 2.25º

The rate of change is of 2.25 degrees per hour.

6 0
2 years ago
For every positive integer n, the nth term of a sequence is given by a_{n} = \frac{1}{n} - \frac{1}{n + 1}. What is the sum of t
Ksenya-84 [330]

The sum telescopes nicely:

\displaystyle\sum_{n=1}^{100}a_n=\left(\frac11-\frac12\right)+\left(\frac12-\frac13\right)+\left(\frac13-\frac14\right)+\cdots+\left(\frac1{99}-\frac1{100}\right)+\left(\frac1{100}-\frac1{101}\right)

\implies\displaystyle\sum_{n=1}^{100}a_n=1-\frac1{101}=\boxed{\frac{100}{101}}

5 0
3 years ago
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