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3 years ago

3/4 divided by 1/5 Please answer soon

Mathematics

2 answers:

lions [1.4K]3 years ago

8 0

3.75
forgive me if i’m wrong but i’m positive it’s correct

Lady_Fox [76]3 years ago

4 0

Answer:

Step-by-step explanation:

im in algebra two so you can trust my answer. happy holidays and stay safe!

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Can anyone help please

Liula [17]

The answer is yes. The triangles are congruent.

I measured them with a ruler and they are the same length.

Hope this helped! c:

8 0

3 years ago

Read 2 more answers

6:20=9:x=x:10=x:60=16:x=12:x

ivolga24 [154]

6:20=9:30=3:10=18:60=16:160/3=12:40

Step-by-step explanation:

The question requires you to find value of x in the ratios given;

Start with the first pair

6:20 = 9:x

6/20 =9/x

6x=20*9

6x=180

x=180/6=30 ⇒⇒ 6:20 = 9:30

The second pair after replacing the value of x=30 will be

9:30 = x:10

9/30=x/10

90=30x

90/30 =x

3=x⇒⇒ 9:30 = 3:10

The third pair after replacing value of x=3 will be

3:10 =x:60

3/10 =x/60

180=10x

180/10 =x

18=x ⇒⇒ 3:10 = 18:60

The fourth pair after replacing value of x=18 will be;

18:60 = 16:x

18/60 = 16/x

18x=16*60

x= (16*60)/18 =160/3

x= 160/3 ⇒⇒⇒ 18:60 = 16: 160/3

The firth pair after replacing value of x=160/3 will be;

16: 160/3 =12:x

16x= 160/3 *12

16x = 160 * 4

x= (160 *4 )/16

x=40

⇒⇒ 16: 160/3 = 12: 40

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Ratios and proportions :brainly.com/question/9512748

Keywords : ratio, value of x, proportion

#LearnwithBrainly

6 0

3 years ago

The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims

kupik [55]

Answer:

Step-by-step explanation:

The mean SAT score is $\mu=600$ , we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it $\sigma$ ) is

$\sigma=48$

Next they draw a random sample of n=70 students, and they got a mean score (denoted by $\bar x$ ) of $\bar x=613$

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis $H_0:\bar x \geq \mu$

- The alternative would be then the opposite $H_0:\bar x < \mu$

The test statistic for this type of test takes the form

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}$

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}\\\\= \frac{| 600-613 |}{48/\sqrt(70}}\\\\= \frac{| 13 |}{48/8.367}\\\\= \frac{| 13 |}{5.737}\\\\=2.266\\$

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>