Hibernation is an adaptation that helps animals to survive cold winters.
Hope this helps.
Answer:
<u><em>All of the above.</em></u>
Explanation:
1. Their watertight skin minimizes moistures loss: <em>Reptiles have a reputation that they are “slimy” when we touch and hold them; however, they have dry skin, which has even fewer glands than mammals or amphibians. The main special feature of their skin is that the epidermis is heavily keratinized with a layer, which also prevents water loss.</em>
2. Amphibians must lay eggs in water or in moist soil to reduce moisture loss: <em>Because amphibian eggs don't have an amnion, the eggs would dry out if they were laid on the land, so amphibians lay their eggs in water.</em>
3. Reptile egg shells are harder than amphibians' eggs: <em>Reptile eggs are coated with a leathery or brittle coating, and the animals that hatch from them are miniature versions of the full-sized animal parent. In contrast, amphibian eggs are transparent and jelly-like. The animals that hatch from them still must go through metamorphosis.</em>
<u><em>Hope this helps you have a better understanding:) !!</em></u>
Vacuole is not a structure used for cellular movement
Answer:
c. 1:2:1
The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.
Explanation:
If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:
- RR- red
- ww - white
- Rw - pink
If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).
<u>From this cross the expected ratios are:</u>
- 1/4 RR (red)
- 2/4 Rw (pink)
- 1/4 ww (white)
So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.
<h3><u>Chi square test</u></h3>
<u>The observed frequencies were:</u>
Total 150
<u>The expected frequencies for our null hypothesis are:</u>
- 1/4 x 150 = 37.5 Red
- 2/4 x 150 = 75 Pink
- 1/4 x 150 = 37.5 white
The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.
If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991
Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.
Answer:
There is no attachment to this question, however, the base sequence on the model built by the student is: CAGCCATC
The options of the bases on the complementary model are:
A) CTACCGAC
B) GUCGGUAG
C) GTCGGAAG
D) GTCGGTAG
The answer is D
Explanation:
A DNA molecule is a polymer biomolecule made up of nucleotide bases. It is a double stranded molecule, with each strand containing nucleotides held together by hydrogen bonds. The pairing of nucleotides in one strand of DNA to another follows the COMPLEMENTARY BASE PAIRING RULE, which states that Adenine binds to Thymine (A-T) while Guanine binds to Cytosine (G-C).
According to this question, a student builds a model containing the base sequence: CAGCCATC, the model that contains bases that are complementary to the ones built by the student is: GTCGGTAG
