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Delicious77 [7]
3 years ago
13

Which of the following is used to name a segment that has an endpoint at point A and another endpoint at point B?

Mathematics
1 answer:
MakcuM [25]3 years ago
4 0

You would write AB with a horizontal line segment over the letters A and B

So you would write this \overline{AB}

If you cannot draw that on your computer, then I would stick to saying "segment AB".

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Pls help me out ty..
OleMash [197]

Answer:

3.14159265359

Step-by-step explanation:

Hope this helps :)

5 0
3 years ago
Read 2 more answers
What is an expression involving division that is equivalent to the expression below?<br> 2/9 x 3/4
Ierofanga [76]

Answer:

2/9 ÷ 4/3

Step-by-step explanation:

5 0
3 years ago
Log2(6x) – log2 (x)-2
ExtremeBDS [4]

Answer:

xlog(64)−xlog(2)−2

Step-by-step explanation:

Simplify 6log(2) by moving 6 inside the logarithm.

log(2^6)x − log(2)x − 2

Raise 2 to the power of 6.

log(64)x − log(2)x − 2

Reorder factors in log(64)x − log(2)x −2.

3 0
3 years ago
- A new rectangular lawn has a
disa [49]

The number of bags of grass seed that are needed to seed the new rectangular lawn is approximately 19 bags .

<h3>Perimeter of a rectangle</h3>

The perimeter of a rectangle is the sum of the whole sides of the rectangle.

Therefore,

perimeter of the rectangle = 298 ft

The width is 67 ft.

Hence

perimeter of rectangle = 2(l + w)

where

  • l  = length
  • w = width

Therefore,

298 = 2 ( l + 67)

298 = 2l + 134

298 - 134 = 2l

164 = 2l

l = 164 / 2

l = 82 ft

Therefore,

area of the rectangle = 82 × 67 = 5494 ft²

285 ft² = 1 bag of grass seed

5494 ft² = ?

cross multiply

number of bag of grass seed to fill the new rectangular lawn = 5494 / 285

number of bag of grass seed to fill the new rectangular lawn = 19.2771929825

learn more on rectangle here: brainly.com/question/16878024

5 0
2 years ago
Select the correct product. (j + 7)(k - 5)
liraira [26]
Foil the equation; j*k, j*-5, 7*k, 7*-5, once you foil add like terms.

jk - 5j +7k - 35 is the final answer
8 0
3 years ago
Read 2 more answers
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