Graph the line for y+1 = - 3(2x - 4) on the coordinate plane.
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<h3>Answer: (4,2)</h3>
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Explanation:
C is at (0,0). Ignore the other points.
Reflecting over y = 1 lands the point on (0,2) because we move 1 unit up to arrive at the line of reflection, and then we keep going one more unit (same direction) to complete the full reflection transformation. I'll call this point P.
Then we reflect point P over the line x = 2 to arrive at the location Q = (4,2). Note how we moved 2 units to the right to get to the line of reflection, and then keep moving the same direction 2 more units, then we have applied the operation of "reflect over the line x = 2"
So we have started at C = (0,0), moved to P = (0,2) and then finally arrived at the destination Q = (4,2). This is the location of C' as well.
All of this is shown in the diagram below.
Answer:
4
Step-by-step explanation:
The general equation of a circle with center (a, b) and radius r is given by the equation;
The constant in the right hand side of the equation is simply the square of the radius;
We have been given the following equation;
(x-3)^2 + (y+1)^2 = 16
Comparing this with the general equation above;